Elimination Method - Solving Systems of Equations │Algebra

This algebra math tutorial explains how to solve systems of linear equations by elimination method. It covers a range of examples, including systems of equations involving fractions, as well as those with infinitely many solutions or no solution. It also shows how to verify/check the solution.
#equations
#systemsofequations
#eliminationmethod
Solving Systems of Linear Equations By Graphing • Solving Systems of Lin...
Solving Systems of Linear Equations By Substitution • Substitution Method - ...
Number of Solutions, Consistent or Inconsistent, Dependent or Independent Systems of Linear Equations • Consistent or Inconsis...
How to Determine If an Ordered Pair is a Solution to a System of Equations • Solving Systems of Lin...
equations, systems of equations, elimination method , solving systems of equations by elimination, how to solve a system of equations by elimination, elimination method , how to solve system of equation by elimination method , how to solve equations by elimination, how to solve system of linear equations by elimination , system of equation elimination method , how to solve a system of equations, solving systems of equations, systems of equations, algebraic method of solving two linear equations, how to do elimination method, how to solve simultaneous equations , solving simultaneous equations , how to solve simultaneous equations algebraically , simultaneous equations elimination method , algebraic method of solving two linear equations, how to solve simultaneous equations using algebraic method , how to solve simultaneous equations by elimination , variable isolation, how to isolate a variable , two equations two unknown, one solution , no solution , infinitely many solutions, solving a system , elimination, algebra , equations, linear equations, gotutor, how to solve simultaneous equations , simultaneous equations elimination method , linear equations ,

Пікірлер: 22

  • @gotutormaths
    @gotutormaths3 ай бұрын

    Graphing method 👉 kzread.info/dash/bejne/haOKt6d8oLrRe8Y.html Substitution method 👉 kzread.info/dash/bejne/ao6uqKSpY6m2dco.html

  • @marksmith1805
    @marksmith18058 ай бұрын

    Wow, this video was a game-changer for me! The way you explained made it crystal clear and easy to understand. Your step-by-step approach, starting from simple examples and gradually increasing the complexity, was incredibly helpful. I learned so much from each example, and by the end of the video, I felt like I had a solid understanding. It's obvious that you put a lot of effort into creating this tutorial, and it's greatly appreciated. I now feel much more confident in my ability to tackle these equations. Thank you and keep up the excellent work!

  • @joseoscar3265
    @joseoscar32654 ай бұрын

    this is what I need it. there are some good in teaching but you are the one that step by step open path into my head, I'm understanding and learning so well and clear with you.

  • @martinmasemola4674
    @martinmasemola46742 ай бұрын

    ❤❤❤u made it look easy

  • @MrIbrahimabutouq
    @MrIbrahimabutouq6 ай бұрын

    The best i have ever seen...simplicity, clearance and neat

  • @giannir7377
    @giannir737720 күн бұрын

    thank you so so much, you have no idea how much you just saved butt, thank you.

  • @samsonwanyoike6959
    @samsonwanyoike69593 ай бұрын

    Good job❤

  • @user-nx6nu5ll9j
    @user-nx6nu5ll9j6 ай бұрын

    Thank you so much

  • @EricaMoore-pg9uf
    @EricaMoore-pg9uf2 ай бұрын

    Thanks, appreciated

  • @AgnesMaekopo
    @AgnesMaekopo29 күн бұрын

    Thanks, that fantastic🎉❤

  • @CHIAERNESTINEKUOKUO
    @CHIAERNESTINEKUOKUO3 ай бұрын

    Na so teacher get sense 😮❤

  • @raizatarusanembalzado26
    @raizatarusanembalzado262 ай бұрын

    Cool!

  • @mehrankhan6658
    @mehrankhan6658Ай бұрын

    😮 thank you

  • @CB-vm2nr
    @CB-vm2nr2 ай бұрын

    Great video. Im a little slow. Can you explain c a little more for me? How come you multiple by 3 and -4? I am sorry

  • @gotutormaths

    @gotutormaths

    2 ай бұрын

    We decided to eliminate the Y variable, right? The coefficient of the Y variable in the first equation is 8 and in the second equation is 6. The least common multiple of 8 and 6 is 24 (3 x 8 = 24 and 4 x 6 = 24). Therefore, we can make the coefficients of Y opposites by multiplying the first equation by 3 and the second equation by -4, or by multiplying the first equation by -3 and the second equation by 4. In both cases, the coefficients of Y become opposites, and when adding the two equations, the Y variable is eliminated. Please let me know if you need further clarification.

  • @sssssunyy

    @sssssunyy

    18 күн бұрын

    @@gotutormathswhy is 4 negative though?

  • @TurkishCypriot
    @TurkishCypriot22 күн бұрын

    7:00 why did you choose second equation instead first equation? 9:28 why did you choose second equation instead first equation again? I still cant understand

  • @gotutormaths

    @gotutormaths

    19 күн бұрын

    Why did you choose the second equation instead of the first equation? It is because the coefficients in the second equation are smaller numbers compared to those in the first equation. It is easier and faster to work with smaller numbers. However, you can also use the first equation and you will get the same answer. Why did you choose the second equation instead of the first equation again? It is because Y is already isolated in the second equation, so you can find it with fewer steps and save time. If you use the first equation, you will get the same answer but it will take more time as you need to do more steps.

  • @Sweetlemon-u5s
    @Sweetlemon-u5s3 ай бұрын

    Is it possible to solve problem D with the substitution method?

  • @gotutormaths

    @gotutormaths

    3 ай бұрын

    Yes it is possible. Please check out problem B in the substitution method video kzread.info/dash/bejne/ao6uqKSpY6m2dco.html

  • @EychaMaula
    @EychaMaula4 ай бұрын

    Y= x/3 -3

  • @raphaelkyalo6093
    @raphaelkyalo6093Ай бұрын

    Wow,fantastic ❤❤❤