Electric Field at a point near Straight Charged Wire | video in HINDI | EduPoint
In this Physics video lecture in Hindi we evaluated the electric field intensity at a point near a straight charged wire of linear charge density λ.
Other relevent topics :
Electric Charge : The property of a proton or an electron, which gives rise to electrostatic force between them, is called electric charge .
It is a scalar quantity.
In S.I., its unit is coulomb (C).
A proton possesses +e charge, whereas, an electron possesses -e charge, where, e =1.6 × 10 ^(-19) C.
Additive nature of charge : - The total charge on an object is equal to the algebraic sum of all the electric charges distributed in that object.
If q1, q2, ……….. qn are the charges distributed in an object, then the total charge on that object,
q = q1+ q2+ …….+ qn
Quantization of charge : - The fact that all observable charges are always some integral multiple of elementary charge e, is known as quantization of charge.
Hence, any observable charge,
q = ± n e
Law of conservation of charge :- Law of conservation of charge states that for an isolated system, the net charge always remains constant.
In other words, charge can neither be created nor be destroyed.
Coulomb's Law :
Coulomb's law in electrostatics states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the magnitudes of two charges and inversely proportional to the square of the distance between them.
Coulomb's constant is having value 9 × 10 ^9 Nm^2 C^(-2).
Absolute permittivity of free space and is equal to 8.854 ×10^(-12) C^2 N^(-1) m^(-2).
The principle of superposition : - This principle states that when a number of charges are interacting, the electrostatic force between two charges is not affected by the existence of the other charges and the total electrostatic force on a charge is the vector sum of all the forces due to other charges.
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Пікірлер: 34
Point charge ka derivation kahin pr bhi nhi mila... Thank you so much sir🧡💛
Excellent! I was stuck in a problem similar to this one and now I've finally got the right answer. Thanks!
Sir apke sabhi aur vedio se ye wala bahut alag hai........... Dimag ka dahi ho gya sir is vedio ko smjne me......... Wase nice vedio sir.....
Thanks a lot you teaching methods is exellent
This video is so informative! I have learned a lot. Scintillating channel!
I understood every bit... Just set playback speed to ×1.75 then there'll be no problem... Thanks EduPoint 👍
@pkhisanjeevkumar2048
3 жыл бұрын
Tumhare jaise sab intelligent nhi h
Thanks for taking my feedback seriously (About slow explanation.. )
got confused but when watched this video all confusions got solved thank you sir
Maja aa gya sir ji. Mast tha. Concept clear ho gya. Question ban gaee 😀🙏 thanks 🤗
Great sir I loved it
Best explanation
Keep it up well done sir
good video
Sir why you have mentioned it as old video.... Is there any new video??
Verry 👍👍👍👍 sir
Sir aapke saare video me sb samajh aata h mgrr ye wale me 3 Barr dkha nhi samajh aa rha h kux
nice video sir
I would like to use this smart board in my class #BHAWNAPHYSICSCLASS so that my effort may come least on board writing.
In your next video which is of same type you take E(perpendicular) as sinØ
Ur voice is adorable
Sir, I am ask questions alpha and beta 90° kyu mane Alpha=beta=π/2 kaise aaya
Apme kaha ki suggested video ki link dunga karke ?
sir ,is this concept is in cbse board
Kindly electric field due to charge disc bhi upload krr dain♥️♥️
Humlog distance y kyun perpendicular wale point se hi lenge explain this
Sir aap chemistry bhi teach kariye
Why do we need to resolve the components of the field Why cant we integrate directly in terms of θ when we obtain the expression :- dE=(kλ/r) dθ at 10:11 Then the result obtained will be(after putting the limits)as follows : E=(kλ/r)(α+β) superb explanation otherwise!!!
sir these derivations are not important in board point of view?? yes or no sir?
why u taken horizontal component as cosØ here..(perpendicular component of E ) ..
@QMSLKR
5 жыл бұрын
Because cos thita equals b/h ......then Eh equals base and r is horizontal so its make cos thita................and listen Eh equal base ......not base
1 M ki mobarik ho
Bilkul samaj me nahi aaya
Out of syllabus I think