Wait hold up and how do you calculate e^2.500… without a calculator 🤣 Bru

@Kashisulu

2 жыл бұрын

Base conversion

@HackerFlavio

2 жыл бұрын

@@Kashisulu I see, thank you

@shabeerp1153

2 жыл бұрын

@@Kashisulu can you explain

@Kashisulu

2 жыл бұрын

@@shabeerp1153 kzread.info/dash/bejne/jGZ1u4-bh9bLqs4.html Refer

@keonscorner516

2 жыл бұрын

@@Kashisulu 10^(2.500… log10(e))

Your videos are always interesting and worth watching. It makes me enthusiastic to do more maths.

@ig__mirza

2 жыл бұрын

Hi

I had forgotten this method and searched a lot for it. Finally got it. Thanks man

Awesome tutorials,learned a lot, clear and precise

thank you! this helped me with an antilog problem

You finally made it make sense. Thank you!

Good explanation. How were the log tables set up?

We solve this exponential to a non-integer power by introducing a new operator.... then reversing it's output by solving a new number raised to a new non-integer power. While correct, this is still thoroughly cursed recursion. "Look it up in tables" is not a satisfying answer.

Good vibe from Morelia. Now I have the two explanations, discovermaths and shurprofe. Continuing with the channel marathon in English and it is ready. Let's go for it.

If there is anything written in addition or subtraction with given ques then what to do please explain

there is someway to do that without ANY calculator? Because it was used to calculate ln 2.1? please, I need to find a way to calculate this

I was on tenterhooks during the first half of the video, wondering whether you were going to use logarithms, or whether you were using a flashy new method that I hadn't heard about. You're right though. Logarithms were an extremely useful tool which were sensational when Napier and others invented and improved them during the 17th century. They were a very important tool for those mathematicians and scientists who were in the process of developing 'the scientific method'.

@discovermaths

4 жыл бұрын

Good point about the sensation logarithms must have caused at the time. Similar to the revolution that electronic computers have brought about in our age.

💗thanks man learned something new and helpful

How nostalgic to bring back my college math, physics, and chemistry 27 years ago. I'm now a physician and had totally forgotten these topics. Thanks for bringing back my memories. If Euler and Newton are alive right now, they will give you many THUMBS UP.

@Sougata_XD

Жыл бұрын

Physician or Physicist

@chauffeur1560

Жыл бұрын

@@Sougata_XD kid named finger

*_Then what will happen with negative base to decimal exponent?_*

I'm not sure changing 2.1^3.37 to e^2.50032 simplifies much of anything. Sure now you can reference a book that lists powers of e, but how were they obtained? This is a circular solution.

@ercop215

2 жыл бұрын

yeah exactly then how to calculate e^2.50032 😂😂

@martinepstein9826

Жыл бұрын

I agree. If the point is to learn the underlying math and not rely on a calculator then what are we using lookup tables for? That's no different from using a calculator. Here is how you can actually do the work by hand. First, to calculate ln(2.1) solve for u such that 2.1 = (1 + u)/(1 - u). The formula is u = (2.1 - 1)/(2.1 + 1) = 11/31. Then use the series expansion ln(2.1) = ln((1 + u)/(1 - u)) = 2(u + u^3/3 + u^5/5 + ... + u^(2n-1)/(2n-1) + ...) Then, to calculate e^2.50032 you can use the famous series e^x = 1 + x + x^2/2 + x^3/6 + ... + x^n/n! + ... By the way, the whole point of using base e is that we get these lovely series expansions. I don't know why base e was used in the video since the log table ended being in base 10.

@Tony-cm8lg

Жыл бұрын

It is circular in that sense, but I think he was just trying to get around the overflow error when evaluating 2^337, not completely avoid using a calculator. Although the title makes it seem like he is teaching how to calculate this without a calculator which he isn’t

@martinepstein9826

Жыл бұрын

@@Tony-cm8lg It's not really circular. You just need to look up in the log table which number has a log of 2.50032

@Tony-cm8lg

Жыл бұрын

@@martinepstein9826 Yes, it’s circular when it comes to the exponent action part. Because then you are left with e^2.50032 and then you are in the same situation that you started in. The only way to calculate this is to use a calculator. Which is fine if that’s what he said in the beginning because he used this trick to circumvent the 2^377 overflow problem.

Amazing editing + amazing content

very useful for calculating pH (log) in chem #jee2023

Thank you soo muchh... Really helped mee

But then, how do early people calculated the values in the log tables in the first place? Also, why you still used a calculator when the title of the video says NOT using a calculator?

thank you sir it really helped me a lot

Great finally I found what I want

@bardock7885

3 жыл бұрын

me too

@v4video41

2 жыл бұрын

Me also

@learn2earn582

2 жыл бұрын

I too

Do the 100th root of 2.1 first and then raise it to the 337 power!

Can we solve this without log table and calculator?

Wait, you can solve e^2.50... in mind but you cant solve 2.1^3.37🤣🤣🤣

Very helpful..thank you sir

Didnt answer my question though. Just ended with e to the power of another decimal which is where we started basically. How would we find the answer without a calculator. We started with a number to a decimal and ended with the same thing but more complicated.

@h1m4n8hu

3 жыл бұрын

Use maclaurin series of e^x

@hyphen8d725

3 жыл бұрын

@@h1m4n8hu Whats that

@fatitankeris6327

2 жыл бұрын

e^x = lim n→∞ (1+x/n)ⁿ That can be calculated by hand.

I needed to be able to do such calculations 100% without calculator. Is that possible cuz mcat seems to think so

Could you show how to do trigeometry without calculator

What is the result at last.... You again got Stuck in solving exponential power

How do u find log of 2.1

Can you help me to how to find the value of exponential power function? For example : e^1.8=??

@manurbhavarya6924

3 жыл бұрын

Use antilog table

@martinepstein9826

Жыл бұрын

Use the series e^x = 1 + x + x^2/2 + x^3/6 + ... + x^n/n! + ...

@abhishekrajput8239

Жыл бұрын

Use scientific calculator 😊

I don't understand the "multiply it by itself so many times" idea. 5 multiplied by itself is 25 - we multiplied it by itself once. Why claim we multiplied it by itself twice?

so, what if I do not have a book???

A slide rule is a calculator!

@discovermaths

4 жыл бұрын

Indeed! Perhaps we should have specified "electronic calculator".

After wasting 3hours in other videos I finally found this.. Thanks!!!

U didn’t teach how to calculate the number though, it was depend on the calculator like ln2.1 and e^2.5

Now,how logarithms were discovered

Thanks a lot Sir

Thank you so much for this wonderful explanation😊😊

@discovermaths

2 жыл бұрын

Thanks!!!!

wow this is truly above my league, as I don´t know how to work with logs and ln´s. But, what about evaluating 4^0.4 without a calculator?

@rohithninan8785

3 жыл бұрын

Take log of 4. Multiply by 0.4 . Take antilog of that result.

@Ni999

2 жыл бұрын

If you can't use logarithms, use the hint from the beginning of the video. 4^.4 = 4^(2/5) = 16^(1/5) 4th root of 16 is 2, so the 5th root is going to be less than that. Guess 1.7, take it to the 5th power and see what you get - too low. Repeat with 1.8, too high. Guess again with 1.75 - high but better. 1.74 is close and you only need a little more. Keep it for as long or as much precision as you need. Or, get a calculator. By the time you need to solve things like 4^.4 you're going to need one.

how did yuo get .7419 for ln 2.1 without a calculator

Awesome thanks alot sir

thanks!!

Sir Can you please make a video on finding powers without decimals

Ah log tables! I used to own a set of these...

@discovermaths

4 жыл бұрын

I kept mine from school - half a century ago!

@gedlangosz1127

4 жыл бұрын

@@discovermaths Sadly my copy disappeared somewhere during one of my many house moves over the years.

but then how do u compute the last e^big decimal?

@manurbhavarya6924

3 жыл бұрын

By antilog table dude

Now tell me using with calculator

Lol in the end all you did was raise 2.71 to 2.5th power... It's the same thing again... Can't do it without calculators

what? it dont make sense 2.1^3.37 it's hard to solve but e^2.500328852 isn't more easy to solve '-'

@MathTidbits

Жыл бұрын

e^2.500328852 is not hard to solve;only impractical. e^2.500328852 ~ (e^2) * (e^.5) * ( 1 + .000328852) doable by hand calculations,but too tedious.

Thnx sir 🙏

Thanks sir

I always wanted to see how a number half of its times would look without calculating. I wish logarithm didn't exist.

Cool video, but you having to raise e to something with a decimal ruins the whole point imo. If you're going to use a calculator at the end. Might aswell have just done the first calculation with a calculator.

How did you jump to 12.185 from 2.5, i did not get that.

@rohithninan8785

3 жыл бұрын

There is an antilog table just like a log table, for performing the inverse function of log. If you look up on that, you get antilog of 2.5 is 12.185

@hyphen8d725

3 жыл бұрын

You set that as the exponent and use base e

how can you solve it by hand when you still ending up with e^2,50003 ... that is decimal number as well so still same problem but different numbers :DD

@CooOOookiez

3 жыл бұрын

that's what i was thinking too lol

@peeepoi1395

3 жыл бұрын

Only 2.5

@hyphen8d725

3 жыл бұрын

well, you could reasonably use 5/2 as an approximation and solve it that way

@hyphen8d725

2 жыл бұрын

@عبدالله tryeasy rewrite it using exponent properties first. 2^2 * 2^1/2

But you used a calculator...

So we cant find answer unless we have logarithmic table. Is it??

@martinepstein9826

Жыл бұрын

Of course we can find the answer without a log table. Someone had to create the log table in the first place, didn't they? Sadly, the video doesn't explain how to do this but you can use the series expansions ln((1 + u)/(1 - u)) = 2(u + u^3/3 + u^5/5 + ... + u^(2n-1)/(2n-1) + ...) e^x = 1 + x + x^2 + x^3/6 + ... + x^n/n! + ... Personally, I don't find solving with a log table any more interesting that solving with a calculator.

@MathTidbits

Жыл бұрын

@@martinepstein9826 e^2.50032= e^2 (e^.5) (e^.00032) e^2 and e^.5 are solvable by hand calculations as long as you know e=2.71828182846 as for e^.00032 is approximated by (2+.00032)/(2-.00032) =1.0003200512 accurate to 12 digits.

@martinepstein9826

Жыл бұрын

@@MathTidbits I've never heard of (2+x)/(2 - x) being used as an approximation for e^x. The difference is only about x^3/12. Pretty clever.

@MathTidbits

Жыл бұрын

@@martinepstein9826 I stumbled upon this by modifiying Newton method of approx. Limit as N approaches infinity [(N+1)/(N-1)]^(N/2) approaches " e "

@martinepstein9826

Жыл бұрын

@@MathTidbits I was thinking about how to get a similar approximation for ln(1+x). We can just invert your formula: 1 + x = e^y ~= (2+y)/(2-y) y ~= 2x/(2+x) Again, for small x the difference is about x^3/12

Lastly he used calculator😂😂😂😂😂😂😂

At 2:24 ... never related so much with a software. I too can't work in this range:(((

Sir I thought you will tell any traditional values to calculate but at the end you had used the calculator. If we have to use the calculator then why not simply get the answer by putting 2.1^(3.37). Sorry to say this sir but if you have to calculate the value of exponential and natural log by using calculator then please change the title of the video. I'm really sorry if I have disrespected your sentiments.

In the end we should use a calculator to get the answer !!! And one more thing !! did you relate to Bill Nighy by any chance ?? you look like him and your voice sounds like him !! Thanks for explanation

Sir can u make me brilliant at maths

@discovermaths

4 жыл бұрын

We'll do our best. Keep watching the videos!

maybe im dumb but i came very close in my head of that answer in 8 or 9 sec just by doing 2 exponant 3 en then i tell my self what is 1 / 2 between 2 exponant 3 and 2 exponant 4

You did not explain "e"

Sadly this can't be used by a 8th grader. I thought I'd be easier

But we have to use calculator to calculate e^x

@WiseSquash

4 жыл бұрын

nope, he explains that you need to use log tables in 'reverse' @5:56

U said we will not use cal. Yet to didnt explain how you got log values from...(id we dont hv log table or any other artificial means)...😒😒😒😒

I still can't process how fractional, non-whole exponents are possible. Seems counter intuitive at first.

How to calculate the approx value of base 10 with power in decimal??? Please reply soon🙏

A calculator isn't more lazy than just reading a log table or a slide ruler. 'real maths', if that's what we are going to call it, would be to approximately find the solution using something like CORDIC or some numerical method.

No no it's beyond my head

best video

Ah i thought u did without using log

2.1 ^3.37 using a simple calculator? Can anyone do it? Without log table

How come when you do 0.517 to the power of 1.3 the answer is 0.424? Surely if your multiying something larger than 1.0 it will be bigger not smaller??

@mattwilliams4265

Жыл бұрын

It’s because you can write it as 0.517^1 * 0.517^0.3. 0.517^0.3 is about 0.81 which * 0.517 means you get 81% 0.517 or about 0.435

@kabivose

Жыл бұрын

0.517 is not greater than 1

Logarithem is not allowed school then to now how what shall we do in India

😂😂 what a great calculator

Wow! Thanks, I got it now.

it doesn't work for me sorry

Sir i knew it but this trick is not going to work in compatative exams.😅

@sarthaksrthkyoutu100

2 жыл бұрын

India study for their stomach

@riteshpandey8586

2 жыл бұрын

@@sarthaksrthkyoutu100 yeah buddy For stomach

I understand why there's so many dislikes 🤣

Didn't he use a calculator after all?

yeah and how are the values in the log table calculated? calculator didn't exist back then. Tell how to calculate the exponent truely by just our hand and knowledge

l am 8th grade and l memorized it

💙

I'm 12 years and i didn't understood anything 😭

Used a calculator. False advertising.

What about this , ⁴√³√2²

@manurbhavarya6924

3 жыл бұрын

Use differentiation

You started too late on KZread,,, Master 😭

Waste Again e power of decimal

"and thats how logarithsms... were.... obtained... in the past..." ah yes, the logarithm tables given to us mortals by the gods! ... ahhh sigh, basically you just told me you dont really know how any of this works, because you dont even know where the numbers in the log tables come from :/ good riddance mate.

Why he all the time smile and make sound by his lip and tounge , he get on my nerve It is very much irritating