What a powerful concept. Hearing this concept for the first time in my 23 years of life. Wondering why this hasn't been taught in high schools.

@SHIVERS445

2 ай бұрын

Same😅

YOU ARE LEGEND IN MATHS..NO TEACHERSHAVE EXPLAINED THIS WAY.. NO ONE

@Rodha

5 жыл бұрын

Thanks

@Rodha

5 жыл бұрын

Thanks

@mindfullmallu7511

3 жыл бұрын

Did u score well?

@shubhneet.x

Жыл бұрын

​@@mindfullmallu7511 did u score well ?

What a Conceptual clearity this man has😮...Thank you Priya Mam and satyam sir fr introducing us to this legend

@swamisharma4666

4 ай бұрын

An UPSC aspirants

simply superb-I totally agree with you sir-Many books skips the divisibility rules of 7,13 etc difficult numbers......

I've been going through multiple places to find the divisibility rule for 7 from a long time now. Your concept explained here seems to be pretty simple and easy to do. Excellent teaching, Thank you Sir.

Explained a difficult concept so flawlessly. Everything makes sense now!

While watching this video i felt like what is the need to learn so much or rules i will just mug the divisibility of each important numbers.....but after completing the divisibility series i came here again to learn this ultimate hack to develop the divisibility rule for any number

Very unique concept ,tweaked congruence modulo property of 7 for 1000 ,exploited minus 1 remainder property and groups of three with signs affixed to them was truly unique . Loved it!

i am watching this video in 2024.. and this is just so useful...thank you sir.. you have made a difference in our lives

I can't express in words, how much I am thankful to you sir🙏...

How easily you summed up such a difficult concept Thank you Ravi sir!

U r simply the best sir....after a very long time somebody has impressed me in this subject

Never heard of this concept before, thankyou so much Sir

Beautiful +Wonderful×Amazing=Superb

Great concept sir I don't have words how to appreciate you sir

The best teaching class ever in online

@faraznadeem7918

3 жыл бұрын

Brother could you explain me in the second question why didnt we write (1+2+3+4+5) As according to formula it was (1*10^5+2*10^4 and so on).

@faraznadeem7918

3 жыл бұрын

@SARTHAK BORA thanks for your concern to help me. Bdw i understood what i wanted to ask

Thank u for clearing my concepts....

What amazing concepts sir

When sor says for any number it is 10^x/N, it's just for odd numbers.

Best teacher ever ❤

grateful to your series, sir!

Amazing explanations 😍

GREAT CONCEPT!!

what a cocept grt way to teach thanks

Sir mujhe cmat ki preparation karni h but uski videos available nhi h utube pe to m yeh vedios se kr lu to jaega kya ya nhi Or yeh complete course h na

Sir we can apply divisiblity of 11 also bcz. 11 is the factor of 33, so 123456 adding alternate dig it and substract like (2+4+6)-(1+3+5) =12-9 =3 remainder very simple Sir let me know it is right or wrong???

thank you so much sir. God bless you.

Amazing sir ..m. Watching your vedios for tcs NQT ...bahut hard work kiya h aapne sir

@Rodha

3 жыл бұрын

Thankyou :)

@truptinarkhede4850

3 жыл бұрын

What is tcs NQT!?

Thank you so much sir.❤❤

divisibility of complex nos like 33 & 7.

In question one why did we write 10^2k and what is k here ??

Thank you sir ❤️

Anyone can tell me that how we will get to know that remainder will come + or - in last question

Thank you Sir🙏

Thank you so much sir

Thanks sir

Can someone please please explain how did he get the remainder of 10×10×10/7 as +6(-1), i know he used basic remainder theorem, but when you use basic remainder it should have been 3×3×3, which is basically 27/7 again, that gives out remainder 2 using basic reminders theorem.

@thatsme61

Жыл бұрын

How are you getting rem as 2? When it's 27/7, 7x3=21 providing the rem of 6, and again 7x4=28 providing the rem of -1. Hope you got it.

At 23:50 ,how can you add and subtract fast ...well done

@prozac8430

Жыл бұрын

789-456= 333 333+123=456

Sir,what will be the remainder for the number 5675354 when divided by 7? Because as per your concept (354+005-675)/7 where i am getting a negative number.

@hardikthakur569

2 жыл бұрын

I think you need to just divide it as -675+354 would be -316 and then further dividing -316 by 7 would give you remainder -1 and just change it to positive by subtracting 1 from 7 which would be 8 and this would be further divided to give you 1 as your remainder. Correct me if this is the right way

@justvibin6601

Жыл бұрын

​@@hardikthakur569 7-1=6

Please answer this, Given 7^3 leaves a remainder of -1, we can then find the remainder for any greater number by making groups of 3, but we also know that 7^6 will leave a remainder of 1. So why can't we make groups of 6? we won't even have to worry about signs? Edit: Leave, I tried it, both works. That's just lengthy.

@monikarathore1550

3 жыл бұрын

Do you know, Where are the questions on LCM and HCF models?

@siddharthjain7766

2 жыл бұрын

you can even find at 15:20 of the Divisibility Rules 4 video, the method you're referring here

@siddharthjain7766

2 жыл бұрын

@@monikarathore1550 kzread.info/dron/HXQiDwicRon0tRuWj6r9HA.htmlplaylists/playlists

When we divide 10^x by 24 remainder +1 or -1 will never come. So, how to proceed in case of 24.

@sakshamgupta3276

3 жыл бұрын

24 = 6*4 so if the no. is divisible by 6 and 4 it will be divisible by 24 also..

shivam kamat (11) 6-8-2021 thank you sir🙏

Divisibility of 13?

Multiple of 10^2 wont work here u should have said every power of 10^2 gives remainder +1 when divided by 33 . As multiple of 10^2 is 200 also which do not give remainder 1 when its divided by 33. Correct me if m wrong :) and ya I really appreciate your videos,you make all concepts so easy for us.THANKS.

@Jainankur789

4 жыл бұрын

10^2 is 100, that gives you a remainder of 1. 10^ 2 is nothing but 10*10.

@janvisoni2619

4 жыл бұрын

@@Jainankur789 thanks for telling me what 10^2 means 😊 u didnt get me read it again... every multiple of 10^2 doesn't give remainder 1 like 200,300,400.. We are talking about numbers like 10^2,10^4,10^6...(every power of 10^2)

@tanyashankar9685

3 жыл бұрын

Yeah I was confused with his phrases too.

@sjsthomasnick3002

3 жыл бұрын

@@janvisoni2619 yah u r right. Its not multiples of 10^2. It is powers of 10 which are multiples of 2.

Why it got so hard ..like you have to multiply the last number with 2 and then subtract that with the remaining numbers .. that one is so easy the this mess

thanks sir u are awesome. sir is this much videos is enough for cat level preparation?

Sir in the divisibility rule of 33 in your example , abcdef divided by 33, you convert it into the form of 10 ^ 2K divided by 33 , so you're taking common 10 to the power 4 and hence the remaining is 10a + b and you write only ab how can we write 10 a + b is equal to a b and 10 C + d is equal to CD, sorry I don't understand I am confused please help me sir or anyone please help me.

@arindamtaak6843

3 жыл бұрын

A 2 digit no ab can be written as 10a+b

@vishusingh3097

3 жыл бұрын

Ohk thanku for rply 😊

@adi_dgaf

2 жыл бұрын

@@vishusingh3097 brother when you write a 2 digit number it can be written in the form 10a + b which can be simplified as ab For ex let us take 24 ..we can write 24 in the form of 10 x 2 + 4 where a = 2 and b = 4 Similarly 3 digit can be written in the form abc

Here you gave questions like which follows order in group of 3,, so what about if such numbers ask like suppose e.g: 1234 / 7. How should we solve it easily?

@vikasnarasapur3251

4 жыл бұрын

1234/7= Make a group of 3 means (001,234)/7two groups So now sign 234 have +be sign and 001 have negative sign( u know this how sign comes from above concept) so now -001+234/7=233/7=2 So the remainder for ur question is 2! I hope u got the answer

Is their anyone having problems sheet topic wise. Then please help me

Want to know how the reminder is +1 =10power 2/33

@snehatsamuel30

4 жыл бұрын

33 x 3 = 99 . therefore 100-99=1

How is 10 to the power 1ef/33 is leaving remainder as 1? I am not getting this

@SHIVAMKUMAR-hi9hb

7 ай бұрын

watch again from 5:35 , and see 10^0/33 is nothing but 1/33 and its remainder is 1. And (10^1.e +10^0. f) can be written as 10^0(ef) this is what he has done

how come 10^3 / 7 reminder is -1? don't understand it 15:38

@adityathakur005

Жыл бұрын

Same doubt

And Exactly "7" dislikes...

Sir if we need all the digits of a no. To find the remainder.. we can just use the calculator to find remainder

Sir Jipmat and Ipmat ki registration date aah gayi hai kya

@sujalkumar8634

Жыл бұрын

have you cleared it !!!??????

Whats the method of divisibility of 6..anyone?

@snehatsamuel30

4 жыл бұрын

Check if the number is even - divisibility test for 2 and then check if sum of digits is divisible by 3 . because 2 and 3 are factors of 6

How to take common? Im nt able to undrstnd

@sakshamgupta3276

3 жыл бұрын

You should take Commen in the form of 10^x and 10^x remainder should be 1 or -1

thankyou

Can anyone explain at 8:55 how 1/33 =1?

@sujalkumar8634

Жыл бұрын

its not 1/33=1 ...its actually reminder when 1 is divided by 33 which goes like 1=33*0+1 where 0 is devisor and 1 is reminder

39×55×73×90×97×54 is divided by 50 then what is remainder i can't solve this type sir

@sjsthomasnick3002

3 жыл бұрын

Ans is 0.

@akshaysonavane8629

3 жыл бұрын

@@sjsthomasnick3002 explain plz

@sjsthomasnick3002

3 жыл бұрын

@@akshaysonavane8629 39×55×73×90×97×54/50 We can divide individually (39/50)R = -11 (55/50)R = 5 (73/50)R = 23 (90/50)R = -10 (97/50)R = -3 (54/50)R = 4 (-11 × 5 × 23 × -10 × -3 × 4)/50 -(55 ×230 × 12)/50 Again divide individually (55/50)R = 5 (230/50)R = -20 (12/50)R = 12 -(5× -20 × 12)/50 (100×12)/50 Again divide individually (100/50)R = 0 (12/50)R =12 (0×12)/50 =0. Ans = 0. Hope it's clear.

@sjsthomasnick3002

3 жыл бұрын

@@akshaysonavane8629 are u preparing for CAT'21?

How did 10 to the power zero divided by 33 become one?

@drigo8192

4 жыл бұрын

To make a no. in point form we have to first multiply by zero. As 1/33 so 0.030 So in the first step when u multiply 33 with 0 you get the remainder 1 . As we are dividing 1 by 33.

@Justsomeguyyoutubing

3 жыл бұрын

10^0 = 1 1/33 = remainder 1 (calculate)

@aryamansrivastava7218

3 жыл бұрын

@@Justsomeguyyoutubing rem should be 0 na? 1/33 1*33=33 Quotient 33, remainder 0???

@sanjeetchandra

Жыл бұрын

Can someone please please explain how did he get the remainder of 10×10×10/7 as +6(-1), i know he used basic remainder theorem, but when you use basic remainder it should have been 3×3×3, which is basically 9/7 again, that gives out remainder 2 using basic reminders theorem.

24:10 456/7 remainder should be 2.correct me if I am wrong.

@growwithbro01

Жыл бұрын

456÷7= 65 and remaindr 1

@vinitpatil8755

Жыл бұрын

@@growwithbro01 65/7=9 further dividing 9 gives remainder 2.

@growwithbro01

Жыл бұрын

@@vinitpatil8755 bhai tu *quotient* ko kyu divide kar rha hai

@kaushikibhatt1874

3 ай бұрын

(123+789)-456 how it became 456/7 can you tell me

mujhe smj nhi aya koi ye smja skta hai -1 remainder kesa find krte hai is video mai 15:30 pe 1000/7 ka remainder -1 kessa find kiya

@legendaryquotes964

16 күн бұрын

Bhai jab divide krega to last mein 20 aayega which is -1 to the multiple of 7 (21) . Jaise 22 is +1 of 21 ....I hope you got it

I tried this method for 17 and 19 but unable to solve bcs there are no 10^n which gives rem of +1 or -1

@HadesBTC

3 жыл бұрын

For 17 do 10^8 = -1 Rem

@HadesBTC

3 жыл бұрын

For 19 do 10^72 = +1 Rem

@HadesBTC

3 жыл бұрын

If You Still unable to understand then leave your insta id will send you step by step and help u to understand

@aryamansrivastava7218

3 жыл бұрын

10^0 ÷ 33 ka rem 1 kaise?

@HadesBTC

3 жыл бұрын

@@aryamansrivastava7218 Question sahi sa batao

Taaliyan bajti rehni chahiye

@anishdubey6721

4 жыл бұрын

Bilkul

How does 101 0 leave rem 1?

@Ukkmeee

Жыл бұрын

imeant 10 to power O

@legendaryquotes964

16 күн бұрын

Divided 0 times , so got 1 remainder

Sir the method is not working in the 6 7 digits

@vyankateshpandey8228

5 ай бұрын

Kindly guide sir

@ashokmacho1932

3 ай бұрын

Question batao Bhai

Sir some questions are there

@Rodha

3 жыл бұрын

what?

🤔🤔🤔🤔🤔70 percent Upar sae gyaaa

13:00 24:00

🌹💜

How 1/7 remainder is 1? 😞

@truptinarkhede4850

3 жыл бұрын

Coz 1 is not wholly divisible by 7 and also we don't want a remainder in fractions as remainders are always in integers.

@truptinarkhede4850

3 жыл бұрын

So 1 is the positive remainder. And -6 is the negative remainder. Every remainder is in +1and -1 form. Ok!

How is the remainder of 56 one?

@ShifaArabi

21 күн бұрын

I also have the same doubt

@legendaryquotes964

16 күн бұрын

Bhai yaha particularly 56 ki baat nhi ho rhi , uska Jo common liya hua multiple 10° hai , uska 33 k respect mein remainder 1 hai ....same concept also applied with 12 .,....I hope you got it

How did 10*10*10/7 became -1 Since ramainder is 6

@Abhijeetkr_2211

4 жыл бұрын

You say that remainder is either 6 or (6-7)=-1. For e.g 19/9= Remainder is 1. 17/9= Remainder is 8 or - 1. I HOPE YOU UNDERSTAND THIS 😊😊

@sibgatullahrahmani6079

4 жыл бұрын

Coz for 6/7 remainder is -1

@elcucuy2236

4 жыл бұрын

negative remainder is -1

@namratasingh5634

3 жыл бұрын

@@Abhijeetkr_2211 thank you😊

I tried the 33 one, i didnt geet the answer

@anilbhai1652

4 жыл бұрын

What's your question exactly ?

@romiljain5107

4 жыл бұрын

@@anilbhai1652 nothing, its clear now!!!

Thank you sir