dictionary in python | Lec-14

In this video, I have talked about the fundamentals of programming and Python. If you complete this, you will be well-versed in using list for different use case.
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Пікірлер: 32

  • @hritikapal683
    @hritikapal6833 ай бұрын

    I was about to ask for the video and here you're with another one👏🏻

  • @chethan248
    @chethan24821 күн бұрын

    totalCost = [] for i in labour: if i == "Mahesh": Cost = 47 * labour["Mahesh"] elif i == "Sumesh": Cost = 43 * labour["Sumesh"] else: Cost = 50 * labour[i] totalCost.append(Cost) print(sum(totalCost))

  • @abhinavsingh2894
    @abhinavsingh2894Ай бұрын

    labour_with_cost = {'Mahesh': 500, 'Ramesh': 400, 'Mithilesh': 400, 'Sumesh': 300, 'Jagmohan': 1000, 'Rampyare': 800} days_labour_worked = [47,50,50,50,43,50] price_list = [] for i in labour_with_cost.values(): price_list.append(i) total_cost = 0 for i in range(min(len(days_labour_worked),len(price_list))): total_cost += days_labour_worked[i]*price_list[i] print(total_cost)

  • @mithleshbarnwal9031
    @mithleshbarnwal9031Ай бұрын

    bhai can i get the json data list which you shown as example for nested dictionary

  • @manish_kumar_1

    @manish_kumar_1

    Ай бұрын

    Zomato resturant data from kaggle website

  • @safiadawood5637
    @safiadawood56372 ай бұрын

    hours_worked = 50 total = 0 labour_with_cost = {"Mahesh":500, "Ramesh":400, "Mithilesh":400, "Sumesh":300, "Jagmohan":1000, "Rampyare":800} hours_absent = {"Mahesh":3, "Jagmohan":7} for k in labour_with_cost: if k in hours_absent.keys(): total += labour_with_cost[k] * (hours_worked - hours_absent[k]) else: total += labour_with_cost[k]* hours_worked print(total)

  • @user-ru2fy8nx1z
    @user-ru2fy8nx1z3 ай бұрын

    My Solution of the Assignment labour_with_cost={"Mahesh":500,"Ramesh":400,"Mithilesh":400,"Samesh":300,"Jagmohan":1000,"Rampyare":800} total=(labour_with_cost["Mahesh"])*47+labour_with_cost["Ramesh"]*50+labour_with_cost["Mithilesh"]*50+labour_with_cost["Samesh"]*50+(labour_with_cost["Jagmohan"])*43+labour_with_cost["Rampyare"]*50 print("Total Labour_cost",total)

  • @rohan5111
    @rohan51112 ай бұрын

    from where to download this zomato data used in this video ?

  • @manish_kumar_1

    @manish_kumar_1

    2 ай бұрын

    Kaggle

  • @gagandeepks
    @gagandeepks3 ай бұрын

    Hi Manish, my solution: labour_with_cost = {"Mahesh":500,"Ramesh":400,"Mithlesh":400,"Sumesh":300,"Jagmohan":1000,"Ram":800} # print(labour_with_cost) labour_absent = {"Mahesh":3,"Jagmohan":7} for name in labour_absent: labour_absent[name] = -labour_absent[name] * labour_with_cost[name] print(labour_absent) Total_days = 50 for name in labour_with_cost: labour_with_cost[name] = labour_with_cost[name] * Total_days print(labour_with_cost) print(f"Total labour cost is {sum(labour_with_cost.values())+sum(labour_absent.values())}") Pls reply if we have better solution, Thanks.

  • @AmitGupta-mu9uv
    @AmitGupta-mu9uv2 ай бұрын

    # Assignment - Total Labour cost if the total working days was 50 out of which Mahesh was absent for 3 days and Jagmohan was abesnt for 7 days. Find out the total labour cost. #I have tried this out without using for loop labourer_with_cost= {"Mahesh":500,"Ramesh":400,"Mithlesh":400,"Sumesh":300} print(labourer_with_cost) labourer_with_cost["Jagmohan"]=1000 labourer_with_cost["Rampyare"]=800 print(labourer_with_cost) print(" A: Total Labour cost for a day: ",sum(labourer_with_cost.values())) print(" B: Total Labour cost for 50 day: ",50*sum(labourer_with_cost.values())) print(" C: Total labour cost for Mahesh for 3 days: ",3*labourer_with_cost['Mahesh']) print(" D: Total labour cost for Rampyare for 7 days: ", 7*labourer_with_cost['Jagmohan']) print("Total Labour cost if the total working days was 50 and Mahesh and Jagmohan was absent for 3 and 7 Days respectively would be A*50 which is B minus (C + D) : ",50*sum(labourer_with_cost.values())- 3*labourer_with_cost['Mahesh'] - 7*labourer_with_cost['Jagmohan']) Output - {'Mahesh': 500, 'Ramesh': 400, 'Mithlesh': 400, 'Sumesh': 300} {'Mahesh': 500, 'Ramesh': 400, 'Mithlesh': 400, 'Sumesh': 300, 'Jagmohan': 1000, 'Rampyare': 800} A: Total Labour cost for a day: 3400 B: Total Labour cost for 50 days: 170000 C: Total labour cost for Mahesh for 3 days: 1500 D: Total labour cost for Rampyare for 7 days: 7000 Total Labour cost if the total working days was 50 and Mahesh and Jagmohan was absent for 3 and 7 Days respectively would be A*50 which is B minus (C + D) : 161500

  • @jigsparikh7961
    @jigsparikh79613 ай бұрын

    Manish can you do a video on decorators. Thanks

  • @manish_kumar_1

    @manish_kumar_1

    2 ай бұрын

    Sure 😊

  • @user-ft2bh2ws4i
    @user-ft2bh2ws4i3 ай бұрын

    Manish Bhai, i am also working in Reliance Jio at RCP Ghansoli. I want to switch into data side roles but not getting calls. Please make a video on how to get data engineering interview calls. I am very very frustrated with my current job.

  • @amazhobner

    @amazhobner

    2 ай бұрын

    Study, update resume, keep applying, Notice period is also a factor for getting calls.

  • @user-ft2bh2ws4i

    @user-ft2bh2ws4i

    2 ай бұрын

    @@amazhobner i have 2 months of notice period. What should i do in this case ?

  • @manangupta4444
    @manangupta44443 ай бұрын

    bhaiya next time se thoda zoom karke code ka video banaoo na.Baki Best Video

  • @manish_kumar_1

    @manish_kumar_1

    3 ай бұрын

    Sure

  • @sonurohini6764
    @sonurohini6764Ай бұрын

    Manish bhai nahi aara hai likhna.

  • @manish_kumar_1

    @manish_kumar_1

    Ай бұрын

    It is completely fine if you are struggling to write code. Aapko dhire dhire aane lagega bas daate rahiyega

  • @vishvajitraodotcom
    @vishvajitraodotcom3 ай бұрын

    Bhai tum Kaun se application pr pen tab use karte hai

  • @manish_kumar_1

    @manish_kumar_1

    3 ай бұрын

    Xournal++