Determine largest prime divisor of 33! - 31! , larger constants than ARML 2012 I-1

33-31 = 2 is MUCH smaller than 33! - 31! which is 37 digits in the 8 undecillion range!
Similar to ARML 2012 Individual Problem 1. Factorial manipulations, in particular 33! = 31!x32x33, and the natural factorization yielded 1055 as a factor which has the prime number 211 as factor. Divisibility checking all the prime numbers less than sqrt(211) finished the proof 211 is the biggest prime factor of this ginormous integer whose Hindu Arabic numeral/decimal form remains unknown!
Congrats to mathematicians Max Schindler, Missouri and Robi Bhattacharjee San Diego for their strong finishes in this much heralded math competition 12 years ago!
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Пікірлер: 6

  • @andreasboe4509
    @andreasboe450919 күн бұрын

    Great puzzle.

  • @MyOneFiftiethOfADollar

    @MyOneFiftiethOfADollar

    19 күн бұрын

    What did you like about this "puzzle"?

  • @andreasboe4509

    @andreasboe4509

    19 күн бұрын

    @@MyOneFiftiethOfADollar 33!-31! looks easy at first glance, and hard at second glance, but it turneed out not to be hard after all. A real world application of 33! and 31! would have a division sign between them, not minus. I love puzzles that either look easy but is hard, or looks hard but is easy. This was both.

  • @MyOneFiftiethOfADollar

    @MyOneFiftiethOfADollar

    19 күн бұрын

    Thx, will try to find an instance of the difference of two factorials having a “real world” application. There is bound to be some type of combinatorics usage for the difference.

  • @sumanprusty1173
    @sumanprusty117319 күн бұрын

    31

  • @MyOneFiftiethOfADollar

    @MyOneFiftiethOfADollar

    19 күн бұрын

    31 is a prime divisor, but not the largest prime divisor. 33!-31!= 31!(32*33 - 1)=31!(5*211). So 211 is largest prime factor