Demystifying the Dirac Delta -

Ғылым және технология

In this video, I explain what the Dirac delta REALLY is - and no, it's not a function, at least in the usual sense!
I always felt unsatisfied by the informal definition of the Dirac delta given in physics or engineering courses, but when I finally learned the rigorous definition, it seemed disconnected to the informal one and not very enlightening. I decided to make this video to connect the two definitions and show how intuition and rigor can (and should!) coexist.
Technical footnote: Sometimes the Dirac delta is presented as a distribution or "generalized function", i.e. a continuous linear functional on the space of smooth compactly supported functions. Distribution theory is very powerful, and the Dirac delta appears when trying to make sense of differentiation of non-differentiable functions, or solving differential equations in a "weak" sense. Despite this, distributions can get quite technical (even the existence of smooth compactly supported functions is a bit technical), so I felt it best to avoid covering them in this video.
Submitted as part of the Summer of Math Exposition 2 (#SoME2) contest.
Timestamps:
00:00 - Introduction
00:25 - Informal Definition
1:45 - Measures
3:08 - The Dirac measure
3:58 - Integration with respect to measures
4:53 - Explaining the sifting property
5:35 - Why infinite at zero?
7:10 - Linear functionals
8:45 - A rigorous definition

Пікірлер: 71

  • @JaGWiREE
    @JaGWiREE Жыл бұрын

    Underrated & underappreciated video. A must watch for anyone planning on going down the measure theoretic probability route.

  • @JaGWiREE

    @JaGWiREE

    Жыл бұрын

    Also enjoyed the subtle but powerful introduction to things like radon-nikodym without explicitly mentioning their names :D

  • @kieransquared

    @kieransquared

    Жыл бұрын

    Thanks! I feel like there’s lots of parts of measure theory that seem really technical but have nice concrete intuition behind them.

  • @ejovo
    @ejovo Жыл бұрын

    I've been a little confused while learning about distribution theory and how the dirac delta function is defined through that lens, so it was really interesting and informative to see how a different branch of mathematics adds intuition and creates a more complete understanding of this object. Thank you for this great video.

  • @kieransquared

    @kieransquared

    Жыл бұрын

    One thing that helped me understand distributions a bit better is the fact that most (but not all) of them can actually be represented by integration against a measure, just like with linear functionals acting on continuous functions. So really, once you get an intuitive feel for what measures do, you just need to account for some "extraneous" types of distributions like the Cauchy principal value and derivatives of the Dirac delta in order to completely characterize distributions.

  • @claudestan6834
    @claudestan6834 Жыл бұрын

    As a former engineering student I have never thought of the Dirac function as anything more than a normalized ideal pulse input. It is really nice to know about the math it originated from. Great video.

  • @tomyproconsul

    @tomyproconsul

    Жыл бұрын

    If I remember correctly it was the other way around. Dirac had used it in physics before mathematicians sorted everything out with it.

  • @aminzahedi308
    @aminzahedi308 Жыл бұрын

    As a physics student whose had way more than his share of suffering from major mathematical itchiness and headache when it comes to the Dirac delta function, I really appreciate your effort and enjoyed the simplicity of the presentation and also think I actually did learn a number of new things; namely, the Riesz-Markov-Kakutani thing. Truth is, even with my preliminary trainings in real analysis, abstract and linear algebra, and even some rudimentary knowledge of basic topology and measure theory, this particular subject is way too advanced to be readily grasped, even by the expert folk with a healthy background in math. I also watched a lot of content under #SoME2 to understand how “renormalization” works and learn its basic principles, but unfortunately it’s one of those difficult, inaccessible materials. Nevertheless, kudos on a great video and hope your channel grows BIG👍🏻❤️

  • @quasaree3912
    @quasaree3912 Жыл бұрын

    This was the clearest interpretation of measure theory I've seen in a while. I feel like your video could really use a better thumbnail to get more views.

  • @kieransquared

    @kieransquared

    Жыл бұрын

    Thanks! Made a quick updated thumbnail, I’m not very artistic but hopefully it’s a bit more eye-catching.

  • @corydiehl764

    @corydiehl764

    Жыл бұрын

    @@kieransquared looks like your video blew up since you changed it haha

  • @johnchessant3012
    @johnchessant3012 Жыл бұрын

    The delta function can also be defined as the limit of Gaussians with mean 0, as variance -> 0.

  • @kieransquared

    @kieransquared

    Жыл бұрын

    Yup! I actually have another video that touches upon this :)

  • @carlaparla2717

    @carlaparla2717

    Жыл бұрын

    In what topological space is this limit taken?

  • @kieransquared

    @kieransquared

    Жыл бұрын

    @@carlaparla2717 You could either take it in the topology of measures, or in the topology of distributions (these are the respective weak* topologies for the space of continuous functions, and the space of smooth compactly supported functions). Basically, a sequence of measures mu_n converges weak* to mu if for all continuous functions, integral(f dmu_n) converges to integral(f dmu). So in this case, the dmu_n would be [n/sqrt(2pi)]*e^{-(nx)^2/2} dx, where the standard deviation is 1/n, and they converge to the Dirac measure.

  • @10babiscar

    @10babiscar

    Жыл бұрын

    @@kieransquared couldn't you just use the uniform distribution to make life easier?

  • @kieransquared

    @kieransquared

    Жыл бұрын

    @@10babiscar That’s true, a uniform probability measure over [-h,h] also converges in the weak* topology to the Dirac measure as h goes to zero

  • @billy-cg1qq
    @billy-cg1qq Жыл бұрын

    Summer of math expedition #some2 is the GOAT of KZread content, hashtags, collabs, or whatever this awesome thing is. Wow!!

  • @wowZhenek
    @wowZhenek Жыл бұрын

    Thank you for this video. It honestly made quite a few of my holes in math knowledge filled. Not just the dirac delta function. I wish you success in this youtube adventure.

  • @JGHFunRun
    @JGHFunRun Жыл бұрын

    So I‘ve actually been thinking about the idea of integrating with dx as an input and not just as the final term, and the Dirac delta seems like it’d be 1/dx at 0 and 0 everywhere else based on the introduction. This would satisfy both properties (no I didn’t accidentally recreate the Dirac delta I just realized how something I was thinking about could be used to create something like it)

  • @PowerhouseCell
    @PowerhouseCell Жыл бұрын

    This was really well done! I can't believe I just found your channel - as a video creator myself, I understand how much time this must have taken. Liked and subscribed 💛

  • @mayatrash
    @mayatrash Жыл бұрын

    This was absolutely fantastic. As somebody doing Many-Body QFT with interactions I always just took it as a given and even though I did some measure theory but never Functional Analysis I was always surprised and bothered by some integrals (for example a rigorous calculation of a particle-hole bubble) and the relationship of things like the Heaviside step “function” and the Dirac “function”. This helped a lot for my intuition and I hope you will gain subscribers soon, your way of explaining is superb

  • @RB-ew6lo
    @RB-ew6lo Жыл бұрын

    Excellent video, enjoyed every second of it! Also didn’t know the Riesz-Markov-Kakatai theorem, so cool!

  • @thehopsful
    @thehopsful Жыл бұрын

    Thanks for the wonderful video - very clear and concise.

  • @mohammadrezaarabieh7743
    @mohammadrezaarabieh7743 Жыл бұрын

    Very clear and intuitive 👌👌

  • @tunafllsh
    @tunafllsh Жыл бұрын

    Very nice! Some true rigorous definitions and explanations!

  • @franciscomacedo8895
    @franciscomacedo8895Ай бұрын

    THANK YOU FOR MENTIONING THE RIESZ MARKOV KAKUTANI THEOREM I have been having analytical mechanics and have been messing around with variational principles, and I've always wondered why we're extremizing one type of functional (namely one where we are integrating) and now I know why! Thank you, I searched everywhere for this!

  • @JCisHere778
    @JCisHere778 Жыл бұрын

    I've been (ab)using the delta function quite a bit lately. Great Video 👌, interpreting delta in the context of measure theory demystifies quite a few things

  • @Hamza-zz3zc
    @Hamza-zz3zc Жыл бұрын

    Very interesting video ! Thanks a lot

  • @reformierteapologetik5166
    @reformierteapologetik5166 Жыл бұрын

    I love this and really appreciate your explanation. Do you have any sources that explains this further by any chance?

  • @pra.
    @pra. Жыл бұрын

    Awesome, and a great intro to measure theory too

  • @iamtraditi4075
    @iamtraditi4075 Жыл бұрын

    This was really really cool! Thank you so much!

  • @9erik1
    @9erik1 Жыл бұрын

    Yessss buddy this is the best SoME2 video so far, though I might be biased as a physicist.

  • @GatesOlive
    @GatesOlive Жыл бұрын

    Really really good video.

  • @tuongnguyen9391
    @tuongnguyen9391 Жыл бұрын

    Oh my god can you do more on measure theory, this is a great video. I did not appreciate measure theory (as an engineer) until I watch your video

  • @syllabusgames2681
    @syllabusgames2681 Жыл бұрын

    I must admit, I am not the target audience for this video. If I had just received a clumsy explanation of the Dirac Delta in some class, this would certainly be a great video! But since this is the first I have heard of this equation, this all felt a bit disconnected from any context. It reminds me of a guide I once read on building linked lists. I understood it, but without any implementation shown, I didn’t know how to use anything I had read or when I would even want to. I don’t really know what the video is missing since I know nothing about this subject you didn’t just tell me, but I think this needs to be a bit more grounded rather than being some small piece of a puzzle I have never seen. For context, I took 4 calculus classes in college. Otherwise, the video is very clear and the visuals are good. Thanks for making it.

  • @kieransquared

    @kieransquared

    Жыл бұрын

    Thanks for the feedback! In practice, physicists and engineers use the Dirac delta to model phenomena that occur over a very short period of time or in a very small region of space. If you vibrate a mechanical system, the input to that system is a sine wave. But if you hit the system with a hammer (imparting a force over a very short period of time), you can model the input as a Dirac delta. Similarly, a distribution of charges create an electric field, and you can solve for the electric field by solving a differential equation. If you take the charge distribution to be a Dirac delta, that models a charge localized to a point, such as an electron, and can therefore solve for the electric field created by an electron.

  • @syllabusgames2681

    @syllabusgames2681

    Жыл бұрын

    @@kieransquared Ok, thanks for the explanation. I actually have a bachelors in mechanical engineering, but every time a class mentioned impulse, they kind of glossed over it and never mentioned any of this.

  • @dekippiesip

    @dekippiesip

    Жыл бұрын

    @@kieransquared in a sense it seems physicists are always ahead of mathematicians in using mathematical concepts. Only after some time mathematicians catch up and make it rigorous, but somehow it always works. It strongly reminds me of calculus early days. When Newton used it concepts like limits and derivatives weren't well defined. He essentially divided 0 over 0, but without any problems or paradoxes emerging. Then only in the 19th century an actual rigorous underbelly emerged with the epsilon delta definition, riemann sums, etc showing it was alright after all.

  • @pavlikkk101

    @pavlikkk101

    Жыл бұрын

    @@dekippiesip because physicists invente things they need, and then come mathematicians to explain "you all are wrong and you can't do like this!" :)

  • @Phito_Sch
    @Phito_Sch Жыл бұрын

    I quit my carrer in formal mathematics last year, i remember concepts from this video in a course i took on the second year. there's always so much to learn in math i will always love it for this, as for me i will be shifting gears into electrical engineering next year i recon it suits me better and truth be told the formalisms and rigor got the best of me but you keep at it shit pays off, or so I've been told.

  • @The_Celga
    @The_Celga Жыл бұрын

    Well explained. Subscribed 👍🏻

  • @sangjunko4898
    @sangjunko4898 Жыл бұрын

    Very nice video!

  • @kieransquared

    @kieransquared

    Жыл бұрын

    thanks! do i know you from somewhere?

  • @firesteel55

    @firesteel55

    Жыл бұрын

    @@kieransquared do I know YOU from somewhere?

  • @geraltofrivia9424
    @geraltofrivia9424 Жыл бұрын

    Beautiful

  • @adolfobahamondealvarez5739
    @adolfobahamondealvarez5739 Жыл бұрын

    Great video 😁

  • @sergiomanzetti1021
    @sergiomanzetti10215 ай бұрын

    Great presentation! Just a note, at 2:47 you should have written m([a,b])=|b-a| . Thanks

  • @gustavk3227
    @gustavk3227 Жыл бұрын

    Phenomenal

  • @lenguyenbach7794
    @lenguyenbach7794 Жыл бұрын

    Your video is not just about understanding the Dirac Delta, it also gave an intuitive way to understand Lebesgue integral, which is pretty hard to visualize while reading the theory of it. Now I can understand why some engineers approximated area of a region by drawing it on a piece of cardboard, then measure its weight and use the "weight to volume" formula to determine the area since volume = height x base-area 🤣Turn out they are just doing what Lebesgue integral did

  • @General12th
    @General12th Жыл бұрын

    Very nifty!

  • @telotawa
    @telotawa Жыл бұрын

    can you 'actually' have it be = infinity if you use surreal numbers? because then omega * eta = 1

  • @alxjones
    @alxjones Жыл бұрын

    I think saying that delta itself is a functional is bit misleading. It's more accurate to say that delta is the kernel of the evaluation functional E_0(f) = f(0). Similarly, shifting delta gives the kernel for E_y(f) = f(y) in general.

  • @kieransquared

    @kieransquared

    Жыл бұрын

    But the kernel of a functional (in the sense of the Schwarz kernel theorem, if we're talking about distributions) is itself a functional - it's perfectly rigorous to say that the Dirac delta is precisely the evaluation functional, and it's how plenty of books define it.

  • @alxjones

    @alxjones

    Жыл бұрын

    @@kieransquared Schwartz asserts a one-to-one correspondence between distributions and maps by the kernel relationship, but I've never seen anyone make a full identification between them as such. Not to say I don't believe you, I'm sure there are references like that. It's not too far off from making an identification between a linear map and its matrix. Still, I would honestly give the same critique to those authors as I have here.

  • @kieransquared

    @kieransquared

    Жыл бұрын

    ​@@alxjones I think pretty much every text on distributions I've seen (notably Hormander's tome on distribution theory) defines the delta distribution as the map delta_a(f) = f(a) (and also wikipedia, Wolfram mathworld, etc). Now that I think more about it, I'm also not even sure what it means for a functional to have a kernel - I'm only familiar with the notion of a kernel for "distribution-valued" functionals, i.e. bounded linear maps from test functions to distributions.

  • @littlecousin5630
    @littlecousin5630 Жыл бұрын

    Isn’t a linear functional a linear map from a vector space V to its field F?* Is the vector space in this case a certain set of functions like C([a,b])?

  • @kieransquared

    @kieransquared

    Жыл бұрын

    Yup, in this case the vector space is C([a,b]), which is a vector space over R. Here we also need the linear functionals to be continuous, since C([a,b]) is infinite dimensional. (linear functionals on finite dimensional spaces are always continuous)

  • @malicksoumare370
    @malicksoumare370 Жыл бұрын

    Neat!

  • @mabm2308
    @mabm2308 Жыл бұрын

    more on measure theory for noobs? that would be awesome. suscribed.

  • @ooos2989
    @ooos2989 Жыл бұрын

    Good video although there was a video by ThatMathThing showing how you could interpret it as an actual function

  • @WindsorMason

    @WindsorMason

    Жыл бұрын

    Can you send the link and/or video title on KZread? I can't seem to find it.

  • @ooos2989

    @ooos2989

    5 ай бұрын

    @@WindsorMason kzread.info/dash/bejne/nXVn1JaNlJWrY6g.html&lc=UgwPJEk0ilR56Sz0Unp4AaABAg

  • @plfreeman111
    @plfreeman111 Жыл бұрын

    Flashbacks to "Optimization in Vector Spaces"

  • @timseguine2
    @timseguine2 Жыл бұрын

    The only critique I would have is, to my mind the usual "working mathematician" way of thinking about the dirac delta is as a type of generalized function called a Schwartz distribution, rather than the purely measure theoretical way it is presented here. But I have a difficult time imagining how to make that an approachable topic for a video like this. You hinted at this briefly by mentioning that it is a linear functional, but then pretty much just abandoned this train of thought.

  • @kieransquared

    @kieransquared

    Жыл бұрын

    True, I considered presenting the Dirac delta as a distribution instead, but I realized it would almost be overkill, as it’s a lot harder to conceptualize distributions compared to measures. Maybe I’ll make another video about distributions at some point. In any case, since measures are a subset of the distributions, I think it’s easier to understand the measure-theoretic approach first before distributions, even if it’s less powerful.

  • @smolboi9659
    @smolboi9659 Жыл бұрын

    3:00 Measures obey subadditivity, the = sign of the boxed equation should be

  • @kieransquared

    @kieransquared

    Жыл бұрын

    The union symbol with a flat bottom denotes disjoint union; also subadditive set functions need not be measures so there needs to be equality there.

  • @smolboi9659

    @smolboi9659

    Жыл бұрын

    @@kieransquared Oh ok thx. I did not know the flat bottom means disjoint union.

  • @wdobni
    @wdobni Жыл бұрын

    i think dirac had a very bad case of the flu during the week that caused him to dream up this nonsense

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