Even after this much year these lecture never get old... Thank you sir for indirectly helping to people like us

what a wonderful genius. Thanks Prof. I have learned a lot. Blessings to you!

prof.n.dhang said that in last classes he will design whole building(slab ,beam,column footing),but there is no video for building design.....this is not fear ,i hv watched all 1-30 lecture pls make a video for it..

am learning much

Could this Method be applied to calculate the deflection on a slab?

many thanks for the useful video. how can i email you? as i have a steel beam deflection question to solve and i hope you can help me thanks again

Sir, Please upload a Lintels in presence of various load.

Sir, thankyou for your wonderful video. I have one doubt on DL. If I have 3m soil load on the beam, then the entire soil load will be treated as DL on beam or not for calculation of deflection of beam. Please clarify , Thankyou.

@annapureddyvenkatayaswanth2209

4 жыл бұрын

Somewhere in the lecture series sir has mentioned imposed dead loads I think you may consider it as dead load

Sir you told to explain the manual design of whole building ?? But when you are uploading the video

@blitzhope

5 жыл бұрын

after 100 years ahhah

@mdahmed9336

5 жыл бұрын

blitzhope 😢

why in finding Igr equation used is bd3/3 instead of bd3/12.?

@isaacpulamte8267

5 жыл бұрын

I used bd³/12 for solving my problem.

@ganeshramaswamy911

5 жыл бұрын

​@@isaacpulamte8267 @ankit Upadhyay Since the top of the rectangle is the centroidal axis.. it's all the same. bd^3/12 is about the centroid of the rectangle. we have to shift it using parallel axis theorem. its bd^3/12 + bd(dy)^2 which for a rectangle about the base comes to bd^3/3 Hope its clear now.

you made mistake while writing the formula of Ir at 28:12 its bx^3/2 you have written bx^2/2 causing me 4 hours to figure out my mistake in the formula.

Sound is not available

@subodhtyagi418

11 ай бұрын

Change your settings

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