Try this next: kzread.info/dash/bejne/q3qXptiMgcrSXbw.html
@nilsalmgren44925 ай бұрын
Convert to exponential form...multiply 1/2 and 1/3 =1/6...convert back to radical form....faster typing than video lol.
@user-yw3iq8wp4k5 ай бұрын
if this isnt fast enough you can do this nth root, mth root of a is equal to (mn)th root of a you can do this by multiplying roots together or try another one nth root mth root oth rooth is equal to (mno)th root of a and soo on soo fourth or when you see mth root (oth root of (a)^p)^n= (mo)th root of (a)^pn or a^(pn/mo) i hope this is helpful
@jefftheseagull5 ай бұрын
Cool
@_Utechpro_5 ай бұрын
³√(√x)) = 6√x
@heyy21055 ай бұрын
Can you teach me how to hold a pen like you 😅
@tobybartels84265 ай бұрын
Multiply repeated indices just like you multiply repeated exponents.
@rexshieh5 ай бұрын
How about x^(1/[√3])=?
@joeythreeclubs
5 ай бұрын
The (square root of three)th root of x.
@TheRook404
5 ай бұрын
1/1^(√3) = √³√x
@tobybartels8426
5 ай бұрын
You don't really need to do anything with that, but if you want, you can rationalize the denominator in the exponent to get x^(√3/3). If you really want to, you could write that as ³√(x^√3), but I wouldn't.
@TaimTeravel5 ай бұрын
If CosecA + CosecB + CosecC = 0 then prove that, (ΣSinA)^2 = ΣSin^2A Can someone help me 😭😭😭
Пікірлер: 15
Try this next: kzread.info/dash/bejne/q3qXptiMgcrSXbw.html
Convert to exponential form...multiply 1/2 and 1/3 =1/6...convert back to radical form....faster typing than video lol.
if this isnt fast enough you can do this nth root, mth root of a is equal to (mn)th root of a you can do this by multiplying roots together or try another one nth root mth root oth rooth is equal to (mno)th root of a and soo on soo fourth or when you see mth root (oth root of (a)^p)^n= (mo)th root of (a)^pn or a^(pn/mo) i hope this is helpful
Cool
³√(√x)) = 6√x
Can you teach me how to hold a pen like you 😅
Multiply repeated indices just like you multiply repeated exponents.
How about x^(1/[√3])=?
@joeythreeclubs
5 ай бұрын
The (square root of three)th root of x.
@TheRook404
5 ай бұрын
1/1^(√3) = √³√x
@tobybartels8426
5 ай бұрын
You don't really need to do anything with that, but if you want, you can rationalize the denominator in the exponent to get x^(√3/3). If you really want to, you could write that as ³√(x^√3), but I wouldn't.
If CosecA + CosecB + CosecC = 0 then prove that, (ΣSinA)^2 = ΣSin^2A Can someone help me 😭😭😭
@TaimTeravel
5 ай бұрын
What is Summation Σ ? How does it even work?
why not just 3*2=6