Complex Numbers : Roots of a cubic equation : ExamSolutions
Complex numbers: finding the roots of a cubic equation.
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11 years on and this video is a blessing- Thank you!
Exactly what I needed! Thank you so much for the perfect explanation
if only my maths teacher had described it like this.so much easier to understand now thank you.
Thank u so mch sir..this was exactly what I was looking for..
Thank you, that has greatly helped my understanding
thank you so much for the upload sir! i wasn't aware of such a straightforward method!
Very nicely taught, thank you very much Sir!
Hi sir, this has been very helpful. Do you mind doing more IB videos? It will be truly appreciated!
This is a great video. Keep it up!
wow superb!!its applicable to all numerical. i have been searching since many days and i got it finally..thanks lot u sir.
@ExamSolutions_Maths
8 жыл бұрын
+Parshu Ram Well done.
That was very help sir. Thank you.
Thank You So Much :) This really helped me a very lot ! Thanks Again !
@ExamSolutions_Maths
9 жыл бұрын
Thilak Kumara Thanks for using.
Thank you so much!
best video on this topic really useful
Thanks soooo much!
@ExamSolutions_Maths
10 жыл бұрын
You're welcome. Thanks for using my site.
@jayagnihotri5807
9 жыл бұрын
ExamSolutions Another fantastic video sir. Can I just ask you is the only way to get the quadratic factor by long division, I used the method but was wondering is there an alternative method. And also how would you obtain the roots of an equation such as x^4-3x^3+2x^2-3x+2? Regards sir :)
@aashsyed1277
3 жыл бұрын
@@ExamSolutions_Maths YOU ARE THE BEST!!
@vanbrecken8147
3 жыл бұрын
a trick : you can watch movies on Flixzone. Been using them for watching a lot of movies these days.
@raphaelsimon1847
3 жыл бұрын
@Van Brecken yea, I have been watching on Flixzone for months myself :D
thankyou so much!!
@ExamSolutions_Maths
3 жыл бұрын
No problem.
Thx was very helpful
Thank yo Sir!
For the roots to be a complex conjugate pair the equation must consist of terms of the form az^3+bZ^2+cZ+d=0 where a does not equal zero and a, b, c, d and are real. d for this equation is imaginary and so this rule does not hold. Your roots are correct though.
at 4:20 you say f(1)=22 but I got 24 on my calculator. And it is the same for -1
For f(1), the answer is 24 not 22. However, great video!! Thanks!
Use one of following substitutions to get quadratic equation Z=U+V Z=U+\frac{7}{3U} You can also get formula for trigonometric function of triple angle with substitution like this Z=2\sqrt{-\frac{7}{3}}\cos{\theta}
thx!
Thank you so much, god bless you good sir.
@ExamSolutions_Maths
6 жыл бұрын
Thank you and you too.
Very good
exams in 13hrs and i comepletely forgot about this topic thank you
@ExamSolutions_Maths
Жыл бұрын
Always welcome
@thecheetahisfasterdandelion
Жыл бұрын
@@ExamSolutions_Maths aced those complex numbers questions! Idk about the rest tho…
when you write down the quadratic formula, I didn't see there is no minus in front of b. Is the formula like that? (-b±square root of b^2-4ac)/2a?
@TWENTYSEVENSTORIES
4 жыл бұрын
b is minus 6, so the negative that is always in the formula cancels this negative out to give positive 6. Hence why there is no negative sign when substituted in to the formula.
What if none of the factors equate the equation to 0
is there a way to this without trial and error
What should I do with the remainder if I get it in a question?
what if we need to find roots in terms of w ?
You're an absolute life saver, thankyou so much for these videos!
@ExamSolutions_Maths
4 жыл бұрын
Saving lives feels good. Thank you and best wishes.
And in this case: x^4+2x^3-x^2+2x+1, how to know its roots?
indeed,......
There should be Z=U-\frac{7}{3U} instead of Z=U+\frac{7}{3U}
❤️❤️❤️🙏🙏
I think I just found the Gordon Ramsay of math
It appears as though I must guess
@Scratchfan321
2 жыл бұрын
After plugging in numbers (Guessing) it worked.
*Quick Fact* If a cubic polynomial given has 2 real roots, those two must be identical.