Complex Analysis L09: Complex Residues

Ғылым және технология

This video discusses the residue theorem in complex analysis and how to compute complex contour integrals around singular points. This culminates in the integral of the function f(z)=1/z.
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This video was produced at the University of Washington

Пікірлер: 21

  • @aftermath4096
    @aftermath4096Ай бұрын

    This is honestly the first time I see such a clear intuitive explanation for the residue theorem. It seems almost trivial now.

  • @parsahamidi
    @parsahamidi9 ай бұрын

    Incredible explanation, the most intuitive description of Laurent series and the residue theorem that I've seen. Don't know how I'd be understanding this stuff without this playlist!

  • @abhiramsatyavolu8078

    @abhiramsatyavolu8078

    2 ай бұрын

    Totally agree with you on this, it’s amazing that we get this for free!

  • @idolgin776
    @idolgin7766 ай бұрын

    I am currently trying to learn the patterns and intuition for complex analysis, and your explanations are awesome. Thanks!

  • @juniorcyans2988
    @juniorcyans29888 ай бұрын

    I'm taking complex analysis this semester. I watched your videos again and again. I love your channel so much!

  • @xinglinli9874
    @xinglinli9874 Жыл бұрын

    Thank you, Steve

  • @Syndicalism
    @Syndicalism Жыл бұрын

    Thank you for such a clear explanation Professor Steve, this video helped make things finally click for me. I wish I had found your channel and playlist last semester when I was still taking Complex Analysis and drowning trying to wrap my head around Residue Theorem. Fortunately I'm able to get your help for Dynamical Systems this semester and in the future when I take Vector Analysis as well as PDE. Keep up the great work!

  • @JoseAlves-ww3pp
    @JoseAlves-ww3pp Жыл бұрын

    Thanks Steve, from Cape Town!

  • @eig_himanshu
    @eig_himanshu Жыл бұрын

    Thanks Steve from India

  • @AZZEDDINE2801
    @AZZEDDINE2801 Жыл бұрын

    Thank you

  • @jimlbeaver
    @jimlbeaver Жыл бұрын

    That’s a remarkable result and it makes me strangely uncomfortable. Really interesting…thanks!

  • @eig_himanshu
    @eig_himanshu Жыл бұрын

    Could you please discuss Complex analysis with Potential Flow

  • @soccerbrain75
    @soccerbrain75 Жыл бұрын

    Will part 8 of this series come back online? Is it currently been reworked?

  • @hoseinzahedifar1562

    @hoseinzahedifar1562

    Жыл бұрын

    kzread.info/dash/bejne/n2V_0bGqptjefps.html

  • @cliffknoll6226
    @cliffknoll62268 ай бұрын

    I think there might be a (serious?) problem in the presentation (I’m an engineer not a mathematician, and truly delighted by the best courses hands down on a variety of subjects). So, the use of the Log depends on the derivation of the fundamental theorem, which you showed on a disk. I looked the fundamental theorem up and it applies on an annulus but requires (i think) splitting the annulus into 2 deformable half annuli. But your last lecture doesn’t mention that, moreover it relies on the Cauchy-Goursat, which specifically cannot tolerate a singularity in the middle of the disk or the closed path isn’t 0, which it can’t be anyway (at this juncture) because it’s i*2pi! I love these lectures but i’m struggling a little with this. I assume the 2 half annuli can be introduced in the last lecture, and toss the (beloved) Cauchy-Goursat out the window? Also, i think this renders all applications of fundamental theorem void (ie all n in Z) without introducing some trick (half annuli, or maybe slit in the domain to exclude the singularity?). I derived 1/z in Cartesian coordinates from scratch, which made me feel a little more secure with this (you did polar in this lecture and i wasn’t sure about separation into two real functions as done with Cartesian in the last lecture (i need to work through polar in more detail later)). If I’ve missed something, or completely whack, please let me know, somebody

  • @strippins

    @strippins

    Күн бұрын

    Lecture 8 now includes a slit in between the two curves to create path not including a singularity?

  • @petervanderwaart1138
    @petervanderwaart1138Ай бұрын

    I think that if you are going to use the 3d plot of the upward spiral, you should be more thorough. For example, what points in the domain are mapped to the axis of the spiral? Log(0) is undefined, but what about points arbitrarily close to the origin? Does the usual 3d depiction show all the surfaces of the range? When you get to the residue theorem, its very easy to think going up the spiral is going around the pole, but it's not. The geometry of the range does not recapitulate the geometry of the domain. It is completely different.

  • @exec9292
    @exec9292 Жыл бұрын

    What's the point of this though?

  • @AABB-px8lc

    @AABB-px8lc

    Жыл бұрын

    In short, it simplify very hard to grasp formula to almost 1 grade level constant.

  • @Andres186000

    @Andres186000

    Жыл бұрын

    The point is that when you want to calculate an integral around a closed loop, you only need to calculate the residue, which is a matter of just evaluating a limit.

  • @ralphhebgen7067

    @ralphhebgen7067

    10 ай бұрын

    One point is it helps to solve certain real-valued integrals that would be hard/impossible to evaluate.

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