Complex Analysis L06: Analytic Functions and Cauchy-Riemann Conditions

Ғылым және технология

This video explores analytic complex functions, where it is possible to do calculus. We introduce the Cauchy-Riemann conditions to test for analyticity.
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This video was produced at the University of Washington

Пікірлер: 30

  • @amittksingh
    @amittksingh5 ай бұрын

    Thanks for providing the necessary context. For Showing us non analytic functions also and putting a meaning around how rare analytic functions are.

  • @treenabalds
    @treenabalds Жыл бұрын

    These videos have been awesome, so far. Your approach to the topic is a little different from previous classes I've taken, and this is actually perfect because it's helping me understand the ideas in more nuanced ways than I had before. Thanks so much!

  • @hoseinzahedifar1562
    @hoseinzahedifar1562 Жыл бұрын

    16:29: 2(1/2), it is like platform 9(3/4)...😅😍, it is as like as this sentence: "your teaching style is like magic".

  • @danielhoven570
    @danielhoven570 Жыл бұрын

    Fantastic series! needed to brush up on this for a mechanics book I'm working through.

  • @yigitrefikguzelses291
    @yigitrefikguzelses29110 ай бұрын

    You are great at these videos, you are really helping me improve my calculus. And i am at highschool its really hard to find stuffs that i can understand with my limited knowledge... so i wanted thank you ❤

  • @marc-andredesrosiers523
    @marc-andredesrosiers523 Жыл бұрын

    I don't recall ever seeing it in 25 years. It'd be nice to see the complex derivatives derived from the polar form. Express the Cauchy-Riemann conditions in polar form, or find an alternative set of necessary conditions that are more easy to express in said form. And, then come back to monomials.With the hope that infinite differentiability of analytic functions is easier to intuit in that form.

  • @ggrsvvrd2683

    @ggrsvvrd2683

    6 ай бұрын

    He finds the Cauchy Riemann conditions in polar in the next lecture

  • @milakshashaey2957
    @milakshashaey29572 ай бұрын

    You gives your best in teaching, awesome.. thank you sir!

  • @samvelsafaryan4698
    @samvelsafaryan4698 Жыл бұрын

    Thank you very much. It's very simple tutorial but very hard branch of math.

  • @erikgottlieb9362
    @erikgottlieb9362 Жыл бұрын

    Thank you. (Additional thanks for including example at end of presentation.)

  • @valentinkadushkin324
    @valentinkadushkin3248 ай бұрын

    wow! this is a gem of a video

  • @curtpiazza1688
    @curtpiazza16883 ай бұрын

    Wow! This is GREAT! This is a whole new world for me! 😂 ❤

  • @annanor9009
    @annanor9009 Жыл бұрын

    Thank you so much for this great lecture and for including your own mistakes along the way. I struggled in math in high school and so gave up on math/science as soon as I was able to, and only decided to try again in my late twenties; after a few years of playing catch-up, I just started a degree in engineering. I spent so long thinking I was just "not a math person" that even having accrued plenty of evidence that I can in fact learn math if I try, it's still easy to assume everyone fundamentally has it together except for me and I'm the only one falling into "stupid" holes all the time. 21:15: would love a primer on the concept of "measure" some time-- I first encountered it when I ended up teaching the lab for the precalculus catch-up class not too long after taking it myself, and found myself saying something similar about an example without thinking about it-- "if I randomly chose a function, it probably wouldn't be the right one... wait, huh... can I say that? what does 'probably' even mean in this context?"

  • @individuoenigmatico1990
    @individuoenigmatico19905 ай бұрын

    1) The principal logarithm function is discontinuous on the entire negative real axis, not just on z=0 hence it is not analytic there. But it is analytic everywhere else. 2) A complex function is analytic if and only if it is R²-differentiable and its partial derivatives verify the Cauchy-Riemann equations.

  • @TheBonaparteReport
    @TheBonaparteReport15 күн бұрын

    Fantastic! My interest in complex analysis was piqued by Roger Penrose’s road to reality, but unfortunately his writing is just too impenetrable for me. You present it in a far more easy to understand way.

  • @Hank-ry9bz
    @Hank-ry9bz2 ай бұрын

    25:00 why expand in a first order taylor series? Wouldn't that ignore higher terms that could affect the result?

  • @ucas5301
    @ucas5301 Жыл бұрын

    Thanks

  • @naturallyinterested7569
    @naturallyinterested7569 Жыл бұрын

    I thought the complex logarithm wasn't analytic on the negative real numbers? It's at least not continuous there. So shouldn't we need to remove (-inf, 0] from C?

  • @georgegoldmanonyidikachijo3784
    @georgegoldmanonyidikachijo37844 ай бұрын

    from my own evaluation of the cauchy reimann equatoin i got [u(∆x, ∆y) - iv(∆x, ∆y) ]/ (∆x + i∆y) is this the same with what you got?

  • @JAYasankarPillai7
    @JAYasankarPillai7 Жыл бұрын

    Couldn't find L04, and L05.....it would be great if they are uploaded. Anyways, thanks a lottttttttttttttttttttttttttttttttttt.

  • @lazaredurand6675
    @lazaredurand66752 ай бұрын

    At 25:35 When you say "you ca pause and this is what you get..." This is really really not evident for me. What mean to expand something out in a first order serie?

  • @Hank-ry9bz
    @Hank-ry9bz2 ай бұрын

    i'm guessing D must be open?

  • @shashwatmangulkar1107
    @shashwatmangulkar11072 ай бұрын

    how does z/2 have two solutions. isn't it a one-one function

  • @shashwatmangulkar1107

    @shashwatmangulkar1107

    2 ай бұрын

    ohh you meant z^1/2 .. then it's True.. Excuse Me

  • @krzysztofciuba271
    @krzysztofciuba271 Жыл бұрын

    A question/suggestion: why do U treat e^z analytic but z^n (only for n=1,2,..) analytic without 0? A practical question in order to reveal some Global Idiocy in physics just by using a complex plain and contour integral as INDEPENDENT from the "path" in such a "perfect/divine" plane - there are just other just real number analytic and geometric solutions but this one is best simple (for the path in Minkowskian space-time)

  • @LeylaAbdulkadir-mq2xq
    @LeylaAbdulkadir-mq2xq4 ай бұрын

    amazing video thankyou : lol it was stupid mistake

  • @broor
    @broor10 ай бұрын

    19:40 z conjugate is not cuspy at all? it is equivalent to f(x,y) = x - yi which has real part x and imaginary part -y which is not at all cuspy. what do you mean?

  • @starsun7455
    @starsun74558 ай бұрын

    I bet prof.Brunton lefthanded.

  • @edwardhuff4727
    @edwardhuff47277 ай бұрын

    It's not the principle of the thing, it's who your pals are. And Riemmann is not your friend, he's some American who got his name mangled at Riker's Island.

  • @younique9710
    @younique9710Ай бұрын

    how is Z^2 a single valued? although Z^2 can be from +Z or -Z?

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