Complex Analysis 16 | Isolated Singularities

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(This explanation fits to lectures for students in their first or second year of study: Mathematics, Mathematics for physicists, Mathematics for the natural science, Mathematics for engineers and so on)

Пікірлер: 20

  • @STgauss3268
    @STgauss32682 жыл бұрын

    When we needed him the most, he comes back.

  • @jaimelima2420
    @jaimelima24202 жыл бұрын

    sin(z)/z^n, sin(1/z) ... These are famous functions! Thanks for putting this course together.

  • @kaspernordenram7832
    @kaspernordenram78322 жыл бұрын

    Amazing series! Please keep making the videos :)

  • @wocalssss
    @wocalssss2 ай бұрын

    Thank you father,you save my exam

  • @brightsideofmaths

    @brightsideofmaths

    2 ай бұрын

    Thank you for the support!

  • @nohaivce2614
    @nohaivce2614 Жыл бұрын

    these videos are so great and super helpful! thank you so much:))

  • @brightsideofmaths

    @brightsideofmaths

    Жыл бұрын

    Glad you like them!

  • @mnada72
    @mnada722 жыл бұрын

    Thank you for the great series here 💯

  • @brightsideofmaths

    @brightsideofmaths

    2 жыл бұрын

    Glad you like them!

  • @hasithanipun4609
    @hasithanipun4609 Жыл бұрын

    Thank you so much!!!!!

  • @brightsideofmaths

    @brightsideofmaths

    Жыл бұрын

    Thank you :)

  • @premkumar-so3ff
    @premkumar-so3ff11 ай бұрын

    Amazing but in definition of isolated singularity your showing the point z0 doesn't belong to open set U but in picture you drawn inside domain U? Or you meant the empty part as U?

  • @brightsideofmaths

    @brightsideofmaths

    11 ай бұрын

    Yes, it's not in U :)

  • @luismaestres5050
    @luismaestres50502 ай бұрын

    Hello. Once I saw this video, I had a question, why does 1/z^2 has a pole in z = 0 of order 2 since the principal part of its Laurent series is 1/z^2?

  • @brightsideofmaths

    @brightsideofmaths

    2 ай бұрын

    Yes, the Laurent series is 1/z^2, so it's a pole of order 2.

  • @luismaestres5050

    @luismaestres5050

    2 ай бұрын

    @@brightsideofmaths But why is that true? Sorry for asking.

  • @brightsideofmaths

    @brightsideofmaths

    2 ай бұрын

    What do you mean? It's just the definition :)

  • @luismaestres5050

    @luismaestres5050

    2 ай бұрын

    @@brightsideofmaths Yes, I misread the definition, since the order is the greatest k such that c_-k is zero without including that maximum (assuming it exists). Thanks for clarify it.

  • @brightsideofmaths

    @brightsideofmaths

    2 ай бұрын

    @@luismaestres5050 You did it by yourself :)