Compact Sets are Closed and Bounded
In this video we prove that a compact set in a metric space is closed and bounded. This is a primer to the Heine Borel Theorem, which states that the converse is true in Euclidean spaces (i.e. R^n).
#Compact #ClosedAndBounded #HeineBorel
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Пікірлер: 30
The techniques used in the proof helped me clarify some other topology properties, thank you so much 👍🏻
Excellent presentation of this theorem. Great idea to start with a metric space. 👍
Amazing video. Thank you so much!
Well done sir!
Thank you so much Prof.
Heine Borel Thm bring me here❤️❤️❤️
I'm hopelessly bad at math, but I love your videos anyway! :)
why bounded set is less or equal to, but not less than? It is clear that
subscribed just from that beautiful "subscribe" pointing
If we were in a general topological space and not necessarily a metric space, how would you define the notion of boundedness?
So simple and clean! I don't quite get why it's necessary when you're showing compact => closed, to choose a ball of radius 1/2n_1, rather than just 1/n_1. Wouldn't the ball of radius 1/n_1 be separated too if S is contained in S_{1/n_1}=compliment(closure(B_(1/n_1))), which has to be disjoint to B_(1/n_1)?
Really, the proof for compact implies closed goes much more smoothly if we use the Bolzano Weierstrass property.
6:28
this is how you prove ?