Great ..now we are aware of character class and its methods, toUpperCase(), toLowerCase()

Really good questions. Thank you!! Please, make videos on questions related to Collection also.

tysm for teaching begneers

i was asked missing and repeating number program for 3.5 lpa package

Excellent

If they really ask these questions I'm gonna go into interviews right now

One more way to do this, will just go on checking with the reference of index value I will check with arr[0] == I+1 if not the missing element is the I+1

@parthjethwani1837

Жыл бұрын

array need to be sorted

@helpinghand6041

Жыл бұрын

@@parthjethwani1837 yes

public static void main(String[] args) { int [] arr = new int []{1,2,3,5, 6,7,8,9} ; int n= arr. length+1; int sum = n* (n+1) /2; for (int i : arr ){ sum -= i; } System.out .printIn("Missing number is "+sum);

please don't do DS and Algo, we can get this easily. Do class related videos like Employee, list of employees , increase their salary, group by etc

if only one no is missing then only answer will work.what if 2 no are missing .

Don't you think for missing number code the formula will result in overflow if n is very very large

@cloudtech5260

Жыл бұрын

Hi Teja, Very good question. This logic can handle upto n = 46300 elements easily. The calculation n*(n +1) will still fit in int data type. If you want even more elements then we can go for long data type.

Birlliant

So you don't need any actual DSA problem solving skills for Capgemini?? Is it that easy or am i missing something

@cloudtech5260

Жыл бұрын

For Capgemini Java 8 is enough. 👍

@rahulkharapkar9962

Жыл бұрын

Cloudtech ,not anymore... I am working on java 11 and it's not this easy for sure they do ask array and some advanced DSA concepts as well.. this looks like fresher interview

@omprakashnaik693

Жыл бұрын

@@rahulkharapkar9962 hii bro

String s = "India is My Country India is My Country"; String s1 = s.substring(0,s.length()/2); String s2 = s.substring(s.length()/2); String result = "\0"; result = s1.toLowerCase(); result += s2.toUpperCase(); System.out.println(result);

@kiranbhopale1249

Жыл бұрын

What is meaning of "\0" ?

@surabhisahu1231

Жыл бұрын

@@kiranbhopale1249 means null Like 0 in integers

@ramakrishnakoonapareddy3251

Жыл бұрын

Ur logic so simple sir

@bhabanisankar1770

Жыл бұрын

String s1=s.substring(0,(s.length()/2).toLowerCase(); String s2=s.substring(s.length()).toUpperCase();

@harshwardhanshetty4683

Жыл бұрын

@@ramakrishnakoonapareddy3251 i think it's readability is simple

Plz post real time questions

@cloudtech5260

Жыл бұрын

Yes will do. 👍

I must have the worst luck, for a 5LAP job, they asked me codewars morse code advance, as a fresher. 🤣🤣

@cloudtech5260

Жыл бұрын

Hi Gaurav, Which company 😁

@gauravkumar6124

Жыл бұрын

@@cloudtech5260 giyzer systems.

@cloudtech5260

Жыл бұрын

Great! Have a wonderful career ahead 👍

@gauravkumar6124

Жыл бұрын

@@cloudtech5260 na, i got rosted in that interview, i didn't know what i am supposed to do😅😅

@gauravkumar6124

Жыл бұрын

@@cloudtech5260 official feedback was that, candidate is arrogant, rude and does not know coding.

Here is the simplest way public class StringQuestion { public static void main(String[] args) { String str="Capgemini Coding Interview Questions Capgemini Coding Interview Questions"; String upper=str.substring(str.length()/2,str.length()).toUpperCase(); String lower=str.substring(0,str.length()/2).toLowerCase(); System.out.println("The final output is "+lower +" " +upper); } }

Sound is too low!

@cloudtech5260

Жыл бұрын

We will fix in upcoming videos!! 👍

This is not an actual capgemini interview....

@cloudtech5260

Жыл бұрын

This is mock interview with actual questions.

If I provide the number in put how u find the last element in this case 10

@cloudtech5260

Жыл бұрын

Hi Ashok, We already know the sum of first 10 numbers using formula sum1 = n*(n+1)/2. We will then take the sum of input array. Missing number = sum1 - sum of input array

He could have taken an variable with initial value of 1 and compare it with every element. If equal, increase value of that variable. Where the variable and element value differ, break the loop and cur value of that variable is the output.

@AshishKumar-cy7dx

Жыл бұрын

For that there will be two for loop.time complexity will be O(n^2).here it is O(n).

@lonestoryteller5430

Жыл бұрын

@@AshishKumar-cy7dx Nope. If the array is sorted and increasing or decreasing by 1, as given in the problem, it will take only linear TC.

@AshishKumar-cy7dx

Жыл бұрын

@@lonestoryteller5430 array is not sorted.for sorting again you need to run two for loop

@lonestoryteller5430

Жыл бұрын

@@AshishKumar-cy7dx No brother. Listen to the problem statement carefully. It says there n numbers are given then the interviewer says suppose 1 to 10 and one number is missing. Also, we don't need nested loops to sort the array. Arrays.sort () function will do it in logN TC

@AshishKumar-cy7dx

Жыл бұрын

@@lonestoryteller5430 you listen and understand problem statement .u can't use inbuilt function in any interview.its is just one of case in sorted order,you have to write logic for all case.

capgi bht chindi company hai package ke mamle me

@Natkhat_reels_n_Vlogss

Жыл бұрын

With 2 year bond😂🤣

String lowerUpperString = new StringBuilder().append(str.substring(0, mid).toLowerCase()).append(str.substring(mid).toUpperCase()).toString();