Cool XFEM simulation for 3D model. Is this a cohesive segment or LEFM approach?

Very helpful video

awesome video.

Thank you so much

I have a doubt, sir, will I be able to simulate a crack with 2 objects, one embedded inside another in XFEM Method?

Can you do the simulation for shaft with a surface radial crack subjected to torque

Can you do radial crack propagation for solid shaft using xfem?

Is 4200 N/m reasonable for the fracture energies?

Hi Vinneth, I have a question about the units. When you write the Young's Modulus in what units are they or in what system of measurement is Abaqus?

@vineeth9295

3 жыл бұрын

Youngs modulus is in N/m^2

@carlosfelipegomezflorez1145

3 жыл бұрын

Thanks Vineeth.

Thanks for sharing this, have you done smeared crack model in Abaqus? or know where I can find full detailed model for this?

@vineeth9295

4 жыл бұрын

🙋‍♂I think you can find research papers of smeared crack model and based on that you can perform the simulation🙌

@abdullaha2915

4 жыл бұрын

@@vineeth9295 I did find some! but inserting the data in Abaqus is different from theory .. I was hoping to see someone did it in Abaqus.. I have the data in theory ready.

I am not getting crack propagation using direct cyclic...what to do..

Hello, could you please tell me how to get the relevant output of XFEM crack propagation?Such as stress intensity factor, crack length, etc

@giangvu6712

2 жыл бұрын

hello, have you found it yet?

Hi! Just a bit of confused about the Max Principle Stress. The Young's modulus you input is 300e9 (300GPa), but why the MPS is only 100 (Pa)? Thanks!

@vineeth9295

4 жыл бұрын

Good Observation Aoki Zyo , I checked the simulation and in that I used Maximum Principal stress as the failure criteria with value as 100 Pa and keeping Youngs Modulus of steel as 200Gpa. The MPS value should have been kept as the yield stress of the steel somewhere around I think 250 Mpa according to MPS criterion. The value 100 Pa was assigned so that crack could propagate easily.

@rahulsrivastava511

4 жыл бұрын

Aoki Zyo ..

nice

Thanks for this video. I've got into a problem when trying to recreate this example. When I try to submit the job, an error pops up saying that there isn't a section assigned to the crack part. Any idea how to solve this?

@vineeth9295

3 жыл бұрын

I think section assignment is not done

@NikitaKaminskyy

3 жыл бұрын

It's just a warning that you can ignore

@omidziaee94

3 жыл бұрын

@@NikitaKaminskyy That's right, thank you.

Hello Vineeth! can i use this same process to make a crack in a concrete cube? I mean without fixing one side

@vineeth9295

3 жыл бұрын

You have to give atleast one dirichlet boundary condition

@kaveeshashamain6856

3 жыл бұрын

Thank you for replying sir, and isn’t there a way to make a crack without fixed boundary condition in abaqus?

@vineeth9295

3 жыл бұрын

As you are talking about tube the length will be large, so try to use plane strain condition and check

Hi Vineeth. Do you know how to model the permeability?

@vineeth9295

3 жыл бұрын

I am not sure but Permeability means ability of fluids to pass through. So will the usage of membrane element help? Edit: Just guessing

I want to learn Abacus software related to my research work my topic is Fatigue behaviour of headed stud shear connectors in steel concrete composite beams

How to model a crack pattern for wall with openings

@vineeth9295

5 жыл бұрын

Just make three domains by using partition cell

How do I plot XFEM crack propagation

@carlosfelipegomezflorez1145

3 жыл бұрын

Finally @H djelloul , do you know how to plot XFEM crack propagation?

I am getting error of ***ERROR :too many attempts made for this increment. Please help me how to resolve it.

@vineeth9295

3 жыл бұрын

I think meshing is the problem, please check the whole video once again

"the following parts have some elements without any section assigned ", this error is coming for the crack plane, can you please suggest why? And how to solve it.

@vineeth9295

3 жыл бұрын

You need to assign section the crack geometry

@biswabhanupuhan7036

3 жыл бұрын

Hello@@vineeth9295, thank you very much for this quick reply, It is not happening, idk why. If I carefully watch your video at 3:38, you assigned only to the cantilever beam, if I am not mistaken but did not to any crack plane. Even if I am doing a manually it is asking for thickness, with any thickness it is giving an error as 'Too many attempts made for this increment.

@vineeth9295

3 жыл бұрын

@@biswabhanupuhan7036 Hey , While making the part for the crack did you select " Shell" And extrusion 1:17

@biswabhanupuhan7036

3 жыл бұрын

@@vineeth9295 yeah exactly same