In this world of paid lectures of substandard quality, Neso is keeping the standards of education better while free🤗

@mandyhiman436

3 жыл бұрын

YEAH totally companies like whitehat are just looting and scamming parents for stuff that are freely available. respect for neso

@mandyhiman436

3 жыл бұрын

@Keaton Heath wow did u get anything from it

@vivekanand9944

3 жыл бұрын

@@mandyhiman436 yes, Virus

Last H.W. ques is a bit tricky. Here is its solution: (83)+(34) 10000011+ 00110100= 10110111. So divide it in 4 bits then we get 1011 and 0111. Here 0111 i.e.79 . So the problem here is when we add 0110 i.e. 6 in the answer we will get wrong answer because 10110111+ 00000110 Here we are adding 0110 i.e.6 in the side of seven i.e.0111 and in sir's problem we were adding 0110 in the side of 13>9. So we only have to take number 11 out and write 1011+ 0110= 10001 now just merge this result and seven we get 100010111 when we write this result in 4 bits we get 000100010111 so its decimal form is 117.

@MUHAMMADUMER-on2nr

4 жыл бұрын

Thanks

@techandnontech1574

4 жыл бұрын

Bro,ur ans is correct but I have some doubt,when u add 6 to 11 side then result violates the 2nd rule of sir please check it

@manasgupta5004

4 жыл бұрын

@@techandnontech1574 yeah thats the point if u got answer can u tell me.

@ribubora5510

Жыл бұрын

Thnk u bro

@jagadeeshwarreddylingaredd6667

Жыл бұрын

Superb 👌

answers for the HW questions-- a) 0111 b) 00010110 c) 00010101 d)000100010111 .. Loved it for sure.... thank You Neso Academy

@classofapnis4982

3 жыл бұрын

mere 3 ans wrong aaraha hai

@divyarajsinhpadhiyar9739

3 жыл бұрын

3 wrong hai iska

@oggy107

3 жыл бұрын

@@divyarajsinhpadhiyar9739 no

@luciferleviathn

3 жыл бұрын

@@divyarajsinhpadhiyar9739 Why? 7+8 = 15 (0001 0101 in BCD)

@sayanikaghosh1890

3 жыл бұрын

Your Answer 3 is wrong because here the addition is greater than 9 and there the final carry is 1 (not 0 ok, if you have 0 in your final carry, you can add 0110 , )

Another example could be when you also have to watch out for when the carry (after adding 6) from a digit in units place makes the digit in the tens place (and/or a carry from a digit in tens place makes the digit in the hundreds place) exceed 9, and so on. You need to add 6 more than once. eg 57+46=103, and 657+346=1003, etc. eg 1 57+46 0101 0111 0100 0110+ ------------------ 1001 1101 (initial sum) 0110+ (add 6) ----------------- 1010 0011 0110+ (add 6) ------------------ 0000 0011 Final Carry=1 0001 0000 0011= 103

@tuantranluuquoc2910

2 жыл бұрын

good stuff

@faizaahmed3438

Жыл бұрын

what happens when we find both the initial sum to be greater than 9 for example we got the initial sum 1011 1101 should we add 6 to both??

I've been looking for an explanation like this for hours. Thank you so much!!!

There was a dilemma whether should I listen your channel which is one from my two selected channels but now I found that your's the best channel..

Thank you for explaining this so well!

Very organized , very neat !!! kudos neso brother

It's very helpful and your Besic electronics lactures concept is cool

Thanks neso academy for giving such unpaid content better than paid ❤️❤️

To all those who are watching this lecture, please don't miss to try the last HW question.

@easylife4932

5 жыл бұрын

YEAH what is the problem ?

@hungryabhinav1022

5 жыл бұрын

i couldn't do the 2nd no. hw question.

@bhogichandini2998

5 жыл бұрын

Sir I am getting wrong answer for last question

@juanitamoss3413

5 жыл бұрын

​@@hungryabhinav1022 7 + 9 = 16 Therefore doing it in BCD addition goes as following: 0111 is the same as 7.... plus 1001 is the same as 9............. Therefore, 0111 plus 1001 = 1, 0000.............. but because you carried the final 1, you have to follow the RULES for whenever you carrying a 1 at the end of the equation.................. We have to follow the rule of ADDING (SIX) to the solution because we had a final carry of 1............. 1, 0000 + 0110 ________ =1, 0110 THEN, you must go ahead and separate the five bit answer of 1, 0110 into eight bits by ADDING three more zero in front of the first 1............... and you will get TWO SETS OF (four bits) of 0001 and 0110................... The first four bits of 0001 is equal to 1 The second four bits of 0110 is equal to 6 CONCLUSION is 16 PROOF: 7+9 = 16

@juanitamoss3413

5 жыл бұрын

​@@bhogichandini2998 83 + 34 = 117 ​Therefore doing it in BCD addition goes as following: 1000 , 0011 is the same as 8 and 3.... plus 0011 , 0100 is the same as 3 and 4............. Therefore, 1000 , 0011 PLUS 0011 , 0100 = 1011, 0111.............. we DID NOT carry anything over at the end of the equation.............We DO NOT add (SIX) to the solution. 1000 , 0011 + 0011 , 0100 _______________ = 1011, 0111 The first four bits of 1011 is equal to 8+2+1 = 11 The second four bits of 0111 is equal to 4+2+1 = 7 CONCLUSION is 117 PROOF: 83+34 = 117

Thank you!!!! Happy teachers day !!!

Thanks mate you saved my day...

Thank you so much for this wonderful explanation

Thanks for the explanation .. U saved me from a presentation tomorrow

Great tutorial.

Thankyou so much sir for teaching us so easily.

My exam is tomorrow and you cleared things on this subject! :D Thanks man! you're the best :)

@ranjeet_sohanpal

Жыл бұрын

Lmao

@ismmayeen5974

Жыл бұрын

us

@aspect6688

10 ай бұрын

How did it go?

@AzureGhost117

10 ай бұрын

Graduated 7 years ago xD@@aspect6688

@AzureGhost117

10 ай бұрын

was able to pass it easily cuz of it

I understand more from u videos thanks a lot,ur way of presentation is perfect ♥️

Thank you so much. I was really confused about it.

Love this channel

Shaandaar. Very nice

After error correction (i.e add 0110) if msb of the number generates a carry it can be considered as a bcd bit, which is happening in the home work problem 4.

nice lectures sir thanks

Thanks sir for valuable lectures..

Thank you so much sir ❤️

Great Video!

what a timing! Tomorrow i have a test about this stuff!

@rhythmpatel5665

6 жыл бұрын

Same dude :)

@obstutors

3 жыл бұрын

I have after an hour

@chainsinghpawar9138

3 жыл бұрын

U r from

@ravikiran3871

3 жыл бұрын

@@obstutors lol, I am writing exam now

tomorrow I have a test thank you for this explaining.

This is so helpful thanks a lot man :)

Thanks a lot, you're awesome!

Thank you

Excellent teaching thankyou

helpful video thanks so much!

saved me straight from hell. Thank you

tnx sir .. it helps me much ...

I just love this channel......🥰

Thank you ssooooooo much!!!, I finally understood it!!!

Thank you so much now cleared about this ❤️❤️

very helpful thanks a lot

Wonderful

A very good explanation sir

Well done!!

Thank you 😊

all thing are well explained and it is easy way to lean

you are great sir ....thnkuuuu so much ......this is the osm presentatin

Great man thanks

thanks a lot!

Thank you...

thnx for ur efforts

Good work .im watching some of your lectures every day and i m using a book for taking notes just like in the class. I prefer it as good formal academic program.

Thank you sir

Thank uh so much!!!

Thank you so much sir

God bless you sir....

Useful lecture

what happens when we find both the initial sum to be greater than 9 for example we got the initial sum 1011 1101 should we add 6 to both??

Hi! Can you recommend a book on this kind of stuff?

You r great sir❤️

What an actual savior

what is the "final carry" in BCD addition. Didn't quite understand that part.

i like the way that you explain this subject but sorry can i ask what is this app that you use it for explain ?

Very clearly explained Sir..ur way of teaching and explaining is awsm...thnks

Simply super thank you sir

Thank you. Very Informative. (Y)

thank u sir for ur advantage ..asm

Exellent Explained❤

thankyou sir God bless u

good job .

Thank so much sir. I learned a lot 😊

@vinodkumar-uf5jc

Жыл бұрын

Third home work problem i am unable to solve pls clarify this

Tq so much

In the last homework question we don't need to add 6 at all as 7 which is less than 9 with final carry 0 it's correct then 11 which is indeed greater than 9 but final carry is 1 which is also correct as mentioned in the lecture. So 83 + 34 which is 117... We get the same result by making pairs of 4.

@MrMeeseeksPiano

2 жыл бұрын

yeah, but then you are representing two digits (11) with a single bcd code (1011) and it isn't even a valid bcd code.That makes no sense

Sir how can u say about final carry as 0 and1

i love neso academy

you are the best of the best

What is meant by the final carry ?

I have a doubt that . should I have to add 6 to every fours bits in BCD addition or only first time only . please clear my doubt

Thanks Sir🙏🙏

1. 0111=7 2. 0001 0110=16 3. 0001 0101=15 4. 0001 0001 0111=117

@shubhamrajak2120

6 жыл бұрын

Radio Mafia 122

@Learning342

6 жыл бұрын

Radio Mafia 117 is correct

@paddu6567

5 жыл бұрын

@@anirudhcodes wrong it will be 117

(i)0111 (ii)10110 (iii)10101 (iv)100010111 Use a small trick :- add the number in decimal [a+b] = (c) then represent c in BCD {with the help of table } Thanks me later

@harshadiwal4423

2 жыл бұрын

lol

@nimishmahajan7538

2 жыл бұрын

4th is 100100010

@banavathubalaji7149

2 жыл бұрын

Tq bro

Great 👏👏👌

Can we represent a decimal number containing farctional part also into BCD representaion ??? For example 183.556 can we convert it into BCD ?

@vivekchauhan4053

3 жыл бұрын

Yes...We can represent....

@vivekchauhan4053

3 жыл бұрын

183.556 in BCD = 000110000011.010101010110

in the second sum,the sum is binary cuz from 9 to less than 9 the binary and bcd is the same,right?

Please make a video on BCD subtraction using 9's complement

How to find Final Carry ?

life saver

1st - 0111 2nd - 00010110 3rd - 00010101 4th - 000100010111

how is the diagram of (for example 83+34) in BCD addition? please help me

which app are u using

Did anyone plz give answer for 48+ 58 in bcd addition..

In the last question, the left pair's sum was greater than 9 ..? Obviously, the answer is 117 but what bout this case ?

Why the final carry is 0 in first example ?

For those wondering, you have to only add 6 once and then not again if the answer again in bigger than 9, just group them into bits of 4.

which software you use,can you please tell me?

#LEGEND

What happens if sum is equal to 9?Do we then differentiate on the basis of final carry?

@kyukyahua

6 жыл бұрын

Adrija Ray Chaudhuri It still remains a binary number with no carry. Checkout the binary code and see whether it is equal to the BCD code. Whenever you get a decimal number of base 10, convert each digit to it's respective binary. The amount of bits will be 2^4n.

sir what if carry is 1 and sum is > 9?

sir, what would happen when final carry is 1 and no is greater the 9?

@Rahul_kumawat98

7 жыл бұрын

Danish Bhatia u ll get a big 0 (ZERO)

@abhilekhdowerah9323

6 жыл бұрын

no such case exist, adding two single digit bcd no. and getting sum greater then 9 and carry 1

@user-fg6ro

6 жыл бұрын

any 4 bit number greater than 9 is actually A (1010b) to F (1111b) in hexadecimal. Hence there cannot be any carry. But when the sum exceeds F, the sum will be 0, and there will be a carry. So your case does not exist.

divide your final answer to 4-bit blocks and consider each 4-bit result with the 1,2,3 conditions. for example 68 + 79 = 0110 1000 + 0111 1001 = 1110 0001 . For last 4 bit (sum 9 F.C:0) add 0110 so the correct answer will be (wrong answer) + (0110 each of the 4 bits), so 1110 0001 + 0110 0110 = 1 0100 0111 is also equals 0001 0100 0111 = 147 in decimal --> Correct answer. Good luck.

I have some prob sir, u added 8+9 ans would be 17 why are separating sum and final carry,I think two conditions are sufficient if sum >9 then add 6 if not then not add 6