Back to Basics: Understanding Value Categories - Ben Saks - CppCon 2019

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Presentation Materials: github.com/CppCon/CppCon2019
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Back to Basics: Understanding Value Categories
You may be familiar with the terms lvalue, rvalue, and xvalue, if only because they occasionally appear in compiler error messages. However, if you have only a vague understanding of what they mean, you're not alone. Lvalues, rvalues, and xvalues aren't actually language features, but rather semantic properties of expressions and sub-expressions. Understanding these properties provides valuable insights into the behavior of built-in operators, the code generated to execute those operators, and the meaning of some otherwise cryptic compiler error messages. Understanding these properties is also essential for working effectively with lvalue and rvalue reference types, as well as overloaded operators.
This session explains why the language distinguishes among lvalues, rvalues, and xvalues. It describes how the semantic properties of lvalues, rvalues, and xvalues are different and how those properties are reflected in the behavior of lvalue and rvalue references.
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Ben Saks
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Videos Filmed & Edited by Bash Films: www.BashFilms.com
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Пікірлер: 51

  • @lsmgeb89
    @lsmgeb893 жыл бұрын

    After I have been reading some other materials about value categories, this lecture really helps me to understand them. Ben explained these concepts in a crystal clear way. Every modern C++ books should have this chapter.

  • @me5ng3

    @me5ng3

    Жыл бұрын

    What materials were you reading about value categories? I'd love to read more on the subject

  • @pmcgee003
    @pmcgee0034 жыл бұрын

    TFW your Basics lecture includes the term Temporary Materialisation Conversion.

  • @Possseidon
    @Possseidon3 жыл бұрын

    Ahhh! I knew what lvalue and rvalue where, but never got my head around glvalue, prvalues and xvalues. Now I finally got it! Absolutely great talk!

  • @jiaweihe1244
    @jiaweihe124411 ай бұрын

    I cannot find the slides file in the github link provided, is there any other place to get the slides?

  • @collapsingspace
    @collapsingspace3 жыл бұрын

    48:14 For people wondering if std::move(T &&a) has rvalue reference to T as parameter how does it work with something like std::move(str) because str is here an lvalue and it's clearly told in the talk that references to rvalue types only bind to rvalues and not lvalues.. There's a deeper concept at play here note that std::move is templatized and the T&& a parameter actually becomes T&a when called like std::move(str)... you can find videos on type deduction on youtube.

  • @pawanadhikari110
    @pawanadhikari1104 жыл бұрын

    The presentation content isn't available in the github .

  • @kamilziemian995
    @kamilziemian995 Жыл бұрын

    Saks family is an family of experts in explaining C++ in a clear way.

  • @orlandoboffill7448
    @orlandoboffill74484 жыл бұрын

    Mr Ben Saks is a gifted teacher!

  • @kamilziemian995
    @kamilziemian995 Жыл бұрын

    I should watch all Ben Saks talks avaliable online.

  • @kamilziemian995
    @kamilziemian995 Жыл бұрын

    Every C++ programmer should watch this video. With exception to Ben Saks and other superprogrammers that already know it content. 😉

  • @ra1n_
    @ra1n_ Жыл бұрын

    1 hour just flew by Whatta teacher !

  • @TernaryHound
    @TernaryHound4 ай бұрын

    Great lecture. I have used these types and move semantics for years and yet this gave me such a more comfortable understanding of the motivations behind these concepts. Well done!

  • @shoulderstack5527
    @shoulderstack55279 ай бұрын

    I didn't know std::thread had the ++ operator. If C++ didn't exist, and someone said they had a great idea for a language, and described C++ as it is today, no one would take it seriously. This is no criticism of the speaker, who has done a great job.

  • @mikkqu
    @mikkqu4 жыл бұрын

    This guy is awesome, I hope to see more of him in the future!

  • @gustafbstrom
    @gustafbstrom7 ай бұрын

    This talk made how to think about C++ value catogories so much more clear to me. Thanks sir!

  • @YourCRTube
    @YourCRTube4 жыл бұрын

    Great talk. Both approachable and exhaustive.

  • @dickpiano1802
    @dickpiano1802 Жыл бұрын

    When people, who want to make things more complex, so others will be in awe get together you get the C++ universe.

  • @syedimadhaqqi4340
    @syedimadhaqqi43406 ай бұрын

    I cannot find the presentation material. Can you please advise a direct link. Thanks

  • @DominoPivot
    @DominoPivot2 жыл бұрын

    I've been working on highly abstract languages for years so that was an excellent refresher.

  • @saeedmahmoodi7211
    @saeedmahmoodi72114 жыл бұрын

    after 2 months of consusions i finally got it Geart job!

  • @RyutlisWang
    @RyutlisWang Жыл бұрын

    Thank you Ben for such clear and thorough explanation of value categories, the best I have seen.

  • @SirToxe
    @SirToxe3 жыл бұрын

    Excellent talk by Ben.

  • @toolmanp3885
    @toolmanp38859 ай бұрын

    This lecture is truly insightful and easy to follow after I tries to study the value categories in cpp references. Huge thanks!

  • @bboysil
    @bboysil2 жыл бұрын

    Perfect introduction to value categories.

  • @JasonMelton1
    @JasonMelton12 жыл бұрын

    Very helpful in untangling these concepts!

  • @tourdesource
    @tourdesource Жыл бұрын

    Clear as water now, thank you Ben!

  • @RahulRahul-pi5fm
    @RahulRahul-pi5fm8 ай бұрын

    Thank you Ben for the presentation.

  • @unclechaelsneckvein
    @unclechaelsneckvein6 ай бұрын

    Exceptionally good presentation.

  • @zehaia
    @zehaia Жыл бұрын

    Best explanation of this subject out there.

  • @guykeren9666
    @guykeren966610 ай бұрын

    Gifted! great talk, Helps to understand the basics (how much I didn't know)

  • @marketqueue8562
    @marketqueue85624 жыл бұрын

    Thanks.... Cleared all my confusion...

  • @qasimijaz1664
    @qasimijaz16648 ай бұрын

    what a great talk, thanks Ben

  • @anatheistsopinion9974
    @anatheistsopinion99743 жыл бұрын

    Beyond excellent!

  • @konradkomisarczyk396
    @konradkomisarczyk396 Жыл бұрын

    Loved the talk

  • @manuvaad
    @manuvaad Жыл бұрын

    Great talk!

  • @janpapaj4373
    @janpapaj4373 Жыл бұрын

    Superb lecture!

  • @CppCon

    @CppCon

    Жыл бұрын

    Glad it was helpful!

  • @Skotopes666
    @Skotopes66610 ай бұрын

    Great talk. Very helpful

  • @aftostok6080
    @aftostok60807 ай бұрын

    This is great.

  • @paulozhang9346
    @paulozhang93462 жыл бұрын

    Amazing, thanks man.

  • @CppCon

    @CppCon

    2 жыл бұрын

    Glad you liked it!

  • @hanzheng173
    @hanzheng1734 жыл бұрын

    very helpful, thanks.

  • @Sabinagirl164
    @Sabinagirl1644 жыл бұрын

    Great talk

  • @NonTwinBrothers
    @NonTwinBrothers4 ай бұрын

    48:45 Alright I'll admit. Intentional or not, that one made me laugh

  • @liveonphoenix5045
    @liveonphoenix50452 жыл бұрын

    @43:08, I don't understand the 'move' assignment overloaded operator that accepts 'rval' or 'temp-val', it is said that it will delete both previous 'lval' that became 'rval' or 'temp-val', whereupon both 's2' and 's3' become 'nullptr'? By moving, do they also mean emptying those two objects?

  • @liveonphoenix5045

    @liveonphoenix5045

    2 жыл бұрын

    Oh, I see, only use move semantic if we know the `src` is no longer required. As a reminder, never miss an excellent talk/seminar/lecture, Keep watching until the end.

  • @nguyendaison27
    @nguyendaison272 жыл бұрын

    Thank you.

  • @CppCon

    @CppCon

    2 жыл бұрын

    You're welcome!

  • @abdelrhmanahmed1378
    @abdelrhmanahmed13783 жыл бұрын

    int x = 6; int z = 10; int& p =x; p = 100; cout

  • @D0Samp

    @D0Samp

    2 жыл бұрын

    Because the target of a reference is defined at assignment and does not change afterwards. "p = z" does not change the reference from x to z, it just assigns the value of z similar to "p = 100". The pointer equivalent looks like this: int * const p = &x; *p = 100; *p = z; // "p = &z" does not work, since the pointer address is const *p = 200;

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