mam ur classes abot asympotatic notations is superb mam.and your voice is too good

Thank you so much madam now I finally uderstand it 😊

In the example you took C2 as 4. However the real world calculations, C2 value should be greater than the sum of 2 constant value on LHS equation. In your example if we take the value of n as 3, then 3n+2 would become 14 and RHS value would be only 12. Hence the equation would be wrong. Review and comment please.

Suppose n=1 , 3n+2< 4n u say

thanks for the video

Thnkew mam... Appreciated🙏❤

How is c1 = 4 a valid value if 3n + 2 = 1 gives 5 <= 4 for n = 1?

Nice explanation mam

Thank you maam

mam the eg u took is wrong the value of c cannot be 4 it should be 5 or more than 5 please recheck urself before posting it bcoz many ppl are going to watch n learn

very good

Tell me the answer for 5n^2 -6n. Plz

n not ...not define in graphical form it can be cut where the c2g(n) cut the f(n) ??

Ma'am I have watching Jenny's lecture, zenat Hasan academy, code with Harry, Learn coding but kuch smjh nhi aya after watching all the video come to your channel.

thank you mam

😊

i dont get how that can be 4n

I don't understand lower bound..y don't we take 2n instead of n.. ?. Plz answer

mam plz sai bataya kre hm aap se he sik te h

Example galat hai