i like how you derive stuff. i see other youtubers just giving formulas and plugging and chugging
@celebrity_rooster7488
3 жыл бұрын
Exactly. Just write that shit on paper.
@NadeemShaikh-ot8yl3 жыл бұрын
This is a very nice trick!! Thanks a lot.
@ugursoydan81874 жыл бұрын
it was very helpful for me. thank you
@chishikiendeavourer86633 жыл бұрын
Wonderful explaination 👍
@guitarttimman4 жыл бұрын
That's good reasoning.
@deenessop59116 жыл бұрын
Hey Eddie. About that proof for the equation of the asymptote, I was just wondering that isn't the multiplication rule for limits: that the lim x-> infinity [f(x)] multiplied by the lim x -> infinity [g(x)] NOT the same as the limit of x-> infinity [f(x).g(x)] I've been taught that multiplication rule for limits only holds true for when x-> a constant value. Is that a correct proof then? Crown Academy > DrDu. Gvng gvng. Eskeetit mums Hehexd
@jeejee3091
3 жыл бұрын
no what Eddie's multiplication rule is the right one
@aashishrimal5793 жыл бұрын
Love from nepal
@joshgun53112 жыл бұрын
The angle between the hyperbola asymptotes is 60 degrees, find the eccentricity, how do we do this question?
@cavelinguam6444 Жыл бұрын
Reallllly helpful
@zizo-ve8ib4 жыл бұрын
May I ask where the rest of this part is because I can't find the video where you do the rest of the derivation
@evajaymusic1322
3 жыл бұрын
I like it
@warrenw68882 жыл бұрын
Isn’t using linear equation the same thing since it’s a straight line?
@christiancarter255
Жыл бұрын
Yes.
@kevinding12042 жыл бұрын
ahhhh I would love to like this video so much but the total amount of likes right now is at 314 and I don't want to ruin it :((((((((((
@LimeriuxasLT6 ай бұрын
hello nice video but sorry not following how u got 1-(a^2/x^2) at 3:48.. cause we divided.... divided what??
@TheDanubeDepleter
5 ай бұрын
He divided the entire radicand by x^2/a^2
@andeslam73705 жыл бұрын
would like to know how to infer -bx/a after knowing bx/a is one of the asymptotes
@Zosso-1618
4 жыл бұрын
Not sure how helpful this is a year after, but I'll give it a shot. When you square root something, there is both a positive and negative variant. The same is true for here because when he took the square root of both sides, there is both a positive and negative version. Like Mr. Woo said, you can just take bx/a and slap a negative onto it to get the other asymptote. I hope that helps!
@aryanbansal6244 жыл бұрын
could you please please arrange the videos it is really hard to watch all hyperbola asymptote videos in order please reply dont ignore it is a humble request
Пікірлер: 21
i like how you derive stuff. i see other youtubers just giving formulas and plugging and chugging
@celebrity_rooster7488
3 жыл бұрын
Exactly. Just write that shit on paper.
This is a very nice trick!! Thanks a lot.
it was very helpful for me. thank you
Wonderful explaination 👍
That's good reasoning.
Hey Eddie. About that proof for the equation of the asymptote, I was just wondering that isn't the multiplication rule for limits: that the lim x-> infinity [f(x)] multiplied by the lim x -> infinity [g(x)] NOT the same as the limit of x-> infinity [f(x).g(x)] I've been taught that multiplication rule for limits only holds true for when x-> a constant value. Is that a correct proof then? Crown Academy > DrDu. Gvng gvng. Eskeetit mums Hehexd
@jeejee3091
3 жыл бұрын
no what Eddie's multiplication rule is the right one
Love from nepal
The angle between the hyperbola asymptotes is 60 degrees, find the eccentricity, how do we do this question?
Reallllly helpful
May I ask where the rest of this part is because I can't find the video where you do the rest of the derivation
@evajaymusic1322
3 жыл бұрын
I like it
Isn’t using linear equation the same thing since it’s a straight line?
@christiancarter255
Жыл бұрын
Yes.
ahhhh I would love to like this video so much but the total amount of likes right now is at 314 and I don't want to ruin it :((((((((((
hello nice video but sorry not following how u got 1-(a^2/x^2) at 3:48.. cause we divided.... divided what??
@TheDanubeDepleter
5 ай бұрын
He divided the entire radicand by x^2/a^2
would like to know how to infer -bx/a after knowing bx/a is one of the asymptotes
@Zosso-1618
4 жыл бұрын
Not sure how helpful this is a year after, but I'll give it a shot. When you square root something, there is both a positive and negative variant. The same is true for here because when he took the square root of both sides, there is both a positive and negative version. Like Mr. Woo said, you can just take bx/a and slap a negative onto it to get the other asymptote. I hope that helps!
could you please please arrange the videos it is really hard to watch all hyperbola asymptote videos in order please reply dont ignore it is a humble request