Thanks is for this video now i can prove this formula!

Thnk u sir❤

Thanks sir❤

Sir Isko exam m ese hi kark e aayenge

@mandeepeducationacademy9431

5 ай бұрын

Description mein notes hain

mere ko nhi aya 😑

@nadim_shaikh_786

5 ай бұрын

Kya nhi aaya brother ?

@arhansaifi7492

5 ай бұрын

To jaker phad

@Sanatandharm_2006

5 ай бұрын

Kya poti nhi aa rhi kya

Mera ko nhi Aya samaj

@Yuvankanand

5 ай бұрын

To glti Teri h

@user-vx6gg1oo7g

5 ай бұрын

@@Yuvankanand ok

@manishyadavji25

5 ай бұрын

Meh bhai ki side hu

@aaxammeer4020

3 ай бұрын

Repeatedly dekho.. And write a couple of times.

Smjh mein nhi aaya fir se 🫤🥹

2S/R kahan se aya?

@VishalKumar-qt9em

4 ай бұрын

It is excess pressure

@rawskeleton876

4 ай бұрын

@@VishalKumar-qt9em Okay.. But how is it equal to 2S/R?

Ratna pdega😢

Bhai kya teacher h ghnta smj nhi aya

@bishalkumar7800

4 ай бұрын

Bro, pehle topic ko atche se padhke Jan ke yaha aoo.....ye derivation channel hai na ki tumko sab samjhane wala.....derivations are important for school so we come here to get a proper way . don't blame any teacher please. If you don't understand then go there are so many channels

Ascent formula Consider a capillary tube of radius r dipped in a liquid of surface tension S and density ρ. Suppose the liquid wets the sides of the tube. Then its meniscus will be concave. The shape of the meniscus of water will be nearly spherical if the capillary tube is of sufficiently narrow bore. As the pressure is greater on the concave side of a liquid surface, so excess of pressure at a point A just above the meniscus compared to point B just below the meniscus 2S p R  Where R is the radius of curvature of meniscus. If θ is the angle of contact then from right angled triangle shown in figure, we have r cosθ R r or R cosθ 2Scosθ p r     Due this excess pressure p, the liquid rises in the capillary tube t height h when the hydrostatic pressure exerted by the liquid column becomes equal to the excess pressure p. Therefore, at equilibrium, we have p hρg 2Scosθ or hρg r 2Scosθ or p rρg