That's a beautiful drawing of a sine wave.

I hope you really understand how great a public service you provide with a channel like this. Thank you.

I have to thank you for making me clearly understand this simple concept for the very first time

Excellent explanation. Better than most of the attempts of my local professors. Thank you : )

you drew that sin wave perfect.

Best (most simple) explanation I have seen. Kudos to you.

@purdueMET

7 жыл бұрын

Thanks :-)

Absolute stunning explanation!

Well done. Nice and super efficient movie

omg thank you so much this is the first time this stuff's made sense to me D:

Please correct me if i'm wrong. The result at 12:40 should read ~ 4 nF = 0,004 uF If i'm wrong, please just delete comment... Best regards

Very informative I liked a lot, but you actualy made a little mistake in a hurry I guess. 3.9*10^-9 supposed to be ~4nano farads.

Great video

great explanation

thank you sir...such a great video..

Very Informative

I dont know if you read this, but great video! Thanks a lot. Good explanation in a really dry subject, at least if you are a beginner.

@purdueMET

2 жыл бұрын

Thanks :-)

super video would you also try to explain reconstruction filters?

Dude you are really good. Natural teacher!! Thanks!!

Very nice and instructive video. Thank you ! Just one small mistake due to hurry, result should be 4 nanofarad instead of 4 picofarad

Thank you :)

Very well presented and explained. Although the filter commits to the requirements, it's not complying to basic rules of design. When designing various parts you should give the most expensive component a fixed commercially available value, then design the rest to fit as much as possible under more commercially available components. In this case, you should have picked the capacitor first, then calculate the resistor. It's easier to find many resistors than capacitor values on real life design.

Thanks a lot

Perfect !

@purdueMET

2 жыл бұрын

Thanks :-)

you cannot exactly sample at 2f rate, because its Nyquist frequency. data will be lost

You are right ;)

If fs=10kHz and the input signal has fmax=5kHz, then the cutoff frec. cannot be less than 5kHz, because then you 'filter' the 5kHz signal. An anti-aliasing filter tries to delete the high frec. signals in order to allow the computer read the signal we want. It is usually used in AD Converters. Anyway, fs is usually 10-20 times higher than the signal frec. and also 10 times higher than the cutoff frec. Sorry for the English... ;)

@jacobvandijk6525

2 жыл бұрын

In MRI the signal-frequency can be 64 MHz and the sampling-frequency is 1.024 samples/sec. (or less). That's a ratio of 1/64.000. How can that be???

Good lecture. 4 nf not pf.

"Fewest number of samples per cycle is two". But how do you know you're sampling the peak and the trough?

@purdueMET

2 жыл бұрын

You don't. The fewest possible number of cycles is two, but that's the ideal case. In practice, you need more than two. All the data acquisition systems I've used sample at more than 2x the maximum frequency. I think the Agilent (used to be HP) system sampled at 2.56x.

@jacobvandijk6525

2 жыл бұрын

@@purdueMET Okay, thanks!

Simple

Something was wrong in your video. Sampling frequency should be larger than double of maximum frequency not equal.

hmn

I like this, but you really look like adam sandler, and should capitalize on that,