10:25 it's disconcerting to be listening with half an ear then suddenly hear yourself being called out 😂 I'll throw this into Wolfram Alpha and call it quits from there 🙈 Beautiful result!

how would even be comparable solving a math problem and speaking to women..... I'm here for a reason am I not?

@7yamkr

23 күн бұрын

☕☕Bcoz maths is about solving problems and women is the problem So we are terrified about problems

@Haxislive766

22 күн бұрын

😂

just cancel out the y's on both sides and you get '" = '", which is trivial and implies y can be any function of x

@maths_505

23 күн бұрын

FINALLY SOMEONE WHO GETS IT!!!

@7yamkr

Күн бұрын

Looks like I've found maths 506

I solved it by letting z=y'. This makes it a lot nicer to integrate. My final result is -2ln|A*cos(B/2*(x+C))|. I tested it on desmos, both our answers work.

This is what Dr. PK solved with his masterful method in his channel. Glad to see you tackle this too

you finally said the thing.. 2B or not 2B

@Samiul_007

22 күн бұрын

SyberMath 😂

Hi, "ok, cool" : 0:18 , 2:17 , 5:10 , 7:07 , 9:57 , "terribly sorry about that" : 2:21 , 10:15 , 7:05 : dz and not dt at the end of the slide.

3:45, I felt that in my soul

Great work. Since cosh is an even function you could also absorb the ±

Unless I'm wrong, in the final answer you can absorb the 2B/A into a new constant. You can also make the sqrt(B) into just B, and as others mentioned, get rid of the +/-. Just helps to clean it up a bit

cosh is symmetric isn't it? So cosh(+-something) = cosh(something) ?

1:40 We can also just multiply both sides by y' then the left hand side is the derivative of (y')²/2 and the right hand side is the derivative of Ae^y.

3:43 I feel personally attacked :@

@zunaidparker

23 күн бұрын

10:25 I feel personally attacked 😂

@IshayuG

23 күн бұрын

@@zunaidparker You were personally attacked x'D

The problem is much easier if you let u=y', it becomes u"=u.u'=(1/2)(u^2)', which becomes u'=(1/2)u^2+C which is easy to integrate. There are three solutions based upon initial conditions: -2 ln |cosh(ax+b)| + c if C -2 ln |cos(ax+b)| + c if C > 0 -2 ln |x+b| + c if C = 0

@bartoszsobolewski1151

21 күн бұрын

Interestingly, the case C

@nolanrata7537

21 күн бұрын

@@bartoszsobolewski1151 Interesting, I hadn't catched these ones!

I actually sloved it a few days ago and it was good differential equation. My solution development was different, i basically used substitution because i dont know any other standard approaches to solve higher order differential equations.(I just graduated from high school, and preparing for a university exam so i didn't had time to start learning higher math). At the end result is same and it was nice to see a different approach to the problem.

Thank you for your interesting ODE.

Nice, thanks!

Depends the woman and depends the math problem. But hiw i dont want take any personal risk..go ahead with maths.

Nice

Can u please solve y".y=a and a is a constant thank u.

This was pretty easy. Much tamer than the integrals you do, or maybe it’s just me? Also where do you get these from?

Literally every single prof in the math department while I was at uni was married. Even about half the grad students (myself included) were married. The inability to talk to girls/guys/insertpreferencehere must be just a physics teacher thing.

2B

Thank U! Enjoyable intelligence!

Hey! Just noticed: Since coshx is an even function, you can throw the plus-minus in the argument out the window and the final answer is a bit cleaner!

@zunaidparker

23 күн бұрын

But the minus one doesn't change, so you can't do that.

@maths_505

23 күн бұрын

@@zunaidparker exactly

@user-dm1tm8uw2o

23 күн бұрын

@@maths_505 wait I thought the -1 was outside the argument

@user-dm1tm8uw2o

23 күн бұрын

​@@maths_505 on the second to last line you closed the parenthesis on the cosh so the -1 is outside

@Mephisto707

23 күн бұрын

​@@maths_505there's a mistake in the final answer, the -1 is outside the cosh, so the plus minus can indeed by removed.

Has anyone tried to perform a check?

3:53 well I am a woman and I sometimes talk to myself when solving math problems so…

I'm gonna have a lot of free time this summer, anyone have any math courses they recommend? (undergrad level)

@adamkucera9094

23 күн бұрын

Complex analysis

@zab_

23 күн бұрын

@@adamkucera9094 good idea! any idea where i could do it?

y'=t...tt'=t"..(1/2)t^2=t'+c...y=-√(2c)(x+C1)th(√(2c)(x+C1)/2)-ln(1-c(x+C1)^2/2)+c2

You forgot a {}^2 in the B that was left out when you completed the square. The mistake then dripped down onto every step next, rip

No y?🥺👉👈

@maths_505

23 күн бұрын

Not this time bro

Got to give good luck to Parker bro, that will be tough. Not as tough as talking to women tho

You talk to women the same way you talk to men. They’re just people

@adamkucera9094

23 күн бұрын

Too dangerous these days.

speaking to a woman is exponentially more difficult !

Really? LOL, how is that even differentiable?

Talking to women is harder

Talking to women is fine. The mistake is listening to them.

@adamkucera9094

23 күн бұрын

Hahahaha, pay that one!