Sir this was absolutely helpful for JEE mains(India)

@jokarmaths7771

2 жыл бұрын

amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html

I would have considered LHS²-RHS² which ends up simplifying to (x-y/2)²≥0 So LHS²-RHS²≥0 LHS²≥RHS² and since they're both positive taking the sqrt doesn't effect the direction

WHat? Multiplying Both sides of Equation by 0 I s valid Mathematical Operation? Please clarify me I am Confused.

@Serizon_

Ай бұрын

Just because multiplying both sides by 0 makes any two equations equal , but that really doesn't lead to a valid way of getting back to the equation we need to prove since 0/0 is undefined. for example x !=y (this is false) - 1 x*0 = y*0 (this statement is true) - 2 But from 2 you can't derive one , since we know that 0 =0 , 2nd point doesn't tell us nothing new. also you can see it algebraically I guess x*0 = y*0 x= y*0/0 0/0 is undefined and y * undefined is undefined. and so this whole becomes undefined and we aren't sure if its equal or not since its "not defined" , only when we define something can we say if its equal or not Like I say does ajead equal mewomnt you would think I am stupid or my keyboard got an issue but the real issue is these two words aren't defined. they are undefined, atleast in the mathematical meaning I don't know I think I bullshited on this one but hope it helps...

Class 11th maths in our country but you explained in good way 👍

@aashsyed1277

3 жыл бұрын

Same for Pakistan.....

@AaruG0411

3 жыл бұрын

🤣🤣🤣

@jokarmaths7771

2 жыл бұрын

amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html

What is the name of book

@jokarmaths7771

2 жыл бұрын

amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html

Does anyone know what school Eddie Woo teaches at ?

@firstname9845

3 жыл бұрын

Cherry brook technology high

@cryptocow9820

3 жыл бұрын

@@firstname9845 oh wow that’s not far from where I live

@jokarmaths7771

2 жыл бұрын

amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html

(x - y)^2 = x^2 + y^2 - 2xy >=0 => x^2 + y^2 >= 2xy. (x + y)^2 = x^2 + y^2 + 2xy >= 4xy. Then since x > 0 and y > 0: (x + y)/2 >= sqrt(xy) as required.

@jokarmaths7771

2 жыл бұрын

amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html

those were fun problems!

First comment. Enjoying these videos.

@jokarmaths7771

2 жыл бұрын

amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html

AM-GM inequality, Year 9 maths in Australia... Complicated proof presentation, Year 9999999 maths in Australia.

@Abhidnya.Deokar

3 жыл бұрын

LOL........ever heard about JEE Adv. of India ?

@particleonazock2246

3 жыл бұрын

​@@Abhidnya.Deokar Yeah, of course.

@jokarmaths7771

2 жыл бұрын

amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html

Which app or program do you use to write? By the way, great explanations!!

@jokarmaths7771

2 жыл бұрын

amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html

Good example, not obvious what one has to do, notice one looking at notes and not an answer to question, so one would still has to decide what to put on the exam, to be very clear that one starts in the right place for writing a proof.

Oh gosh. Again Eddy. It is ABSOLUTELY acceptable to work from the RTP, just use if and only if arrows all the way down! Which we can do since x and y are positive. A lot of mental gymnastics over a failure to utilise reversible implication...

I think the easier way is solving using a system of equations you get from the partial derivatives

@firstname9845

3 жыл бұрын

This is highschool

@xsamsungg5735

3 жыл бұрын

@@firstname9845 You learn multi-variable calculus in high school too

@firstname9845

3 жыл бұрын

@@xsamsungg5735 not in australia

@jokarmaths7771

2 жыл бұрын

amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html

@jokarmaths7771

2 жыл бұрын

@@firstname9845 amazing .........kzread.info/dash/bejne/mpib2NeIgtGrmaQ.html