Thank u soo much po mam sana matutunan ko ,ngwork na ak govt pero hndi PA ako nkakapasa said csc exam😪

Belen is b years old now. Her daughter's age is 7 more than 1/5 her age. Write an algebraic expression for her daughter's age.

number 7 total age po nila is 36+31= 67? diba po dapat total age nila sa present is 79- 6= 73?

Finally i got this 😊😊😊 Thank you very much maam 😊😊 PS... I hope more tutorial pa po maam kasi you really helped us a lot.. Godbless po and be safe!!

10. The sum of the ages of a father and son is 56. Four years ago the father was 3 times as old as the son. Find the present age of each. Now -4 Father 56-x 3(x-4) Son x x-4 Solution: Put negative (-) 4 on the Eq. of Father 56-x-4 = 3(x-4) - (56-4=52) 52-x = 3x-12 - (52+12=64) (3x+x=4x) 64 = 4x - (64/4=16) 16=x 56-x 56-16 = 40 Age of Son = 16 Age of Father = 40

9. Now -4 The sum of the ages of John and Mary is 32. Four years ago, John was twice as old as Mary. Find the present age of each. John 32-x 2(x-4) 32-(12) = 20 Mary x x-4 Solution: Put negative (-) 4 32-x-4 = 2(x-4) 28-x = 2x-8 36 = 3x 12 = x Age of Mary = 12 Age of John = 20

John iz for timz az old azz marthA

panu po solution no. 9 and 10 9. The sum of the ages of John and Mary is 32. Four years ago, John was twice as old as Mary. Find the present age of each. 10. The sum of the ages of a father and son is 56. Four years ago the father was 3 times as old as the son. Find the present age of each.