Thank you for sharing, this is very well explained and to-the-point.

I have referenced this video multiple times. THANK YOU! :)

Thank a lot for the video but I have a question: I have a stirred tank with an emispherical bottom where the origin of axes is a the lowest point of this bottom, to evaluate the torque, should I change the cross product? Or does it remains always "0*iHat+0*jHat+0*kHat-coords"? I hope my question is clear. Thank you very much in advance

How can I download the file?

thank you for the great video! But i have a additional question: how can i calculate my thrust for a Propeller from my forces? thank you very much :)

@ConselfCompany

7 жыл бұрын

Well .. it's not very difficult ... thrust is the product between mass flow and velocity ... so you can use filters similar to the ones used in here to obtain the result you want!

Hello friend, this is a good video, I learned from you. Only one thing, torque is a product of rxf and in your video you put Fxr.

@RzogL

2 жыл бұрын

Yes, but he was also defined r from the origin to the force application point, which is the wrong way round. Since AxB = - BxA, his Fxr works out the same as RxF, if R is defined as coords-0*iHat-0*jHat-0*kHat.

hi, can we calculate where the centre of lift is? thank you

@Cuneyto12

Жыл бұрын

Hello , I want to determine the centre of lift either but couldnt find yet. Do you know how to find that, thanks in advance.

Your video is great, However i have one doubt. To calculate force you are adding (p*normals+wallshearstress). The unit of wallshearstress is N/m2. It is stress, how we can say it as force. Please clarify.

@ConselfCompany

7 жыл бұрын

Remember that after that operation everything there is a surface integrals!

@madhankumar59

7 жыл бұрын

CONSELF Thank you very much

@HoaiThanh-wm6ze

4 ай бұрын

@@ConselfCompany I think the force (p*normals-wallshearstress)*rho. ???