its crazy how this 8 minute video did so much more to teach me this concept then a whole semester long biochemesty class ever could

@TheScienceClassroom

2 жыл бұрын

I'm so glad it helped!

HAHAHAHA idk what's so funny, but the acids are laughing at me

@solaimanwahab5286

4 жыл бұрын

bro you on some acid stuff and i dont mean the chemicals haha

@hannah6133

4 жыл бұрын

yall's comments are so underrated lmao

God bless you man. Chem final 14hours(tomorrow) and here i am pulling off an all nighter. Wish i had saw this video before hand because i spent 3 days on this topic with our notes and it didnt make any sense. Your videos with practice taught me in 30minutes

This was EXTREMELY helpful.Thank you for taking your time to make this video.👍🏽

Very helpful 8 hours before my P. Chem Final

@studyharder8360

3 жыл бұрын

did you pass?

@migster8570

2 жыл бұрын

did you pass?

@TheFG177

2 жыл бұрын

@@migster8570 I did! I've since graduated and started my career

@TheFG177

2 жыл бұрын

@@studyharder8360 I did!

@celeste2221

2 жыл бұрын

@@TheFG177 ayeee congrats!!

I've watched half a dozen videos trying to understand Ka/pKa and this is the first one I get. good vid.

amazing, very helpful in me brushing up on a bit of gen chem for my biochem class! clear and to the point, thank you

Thank you so much! Now it makes perfect sense

Omg u cleared my years of doubts so easily.. our professor take weeks to finish one topic still it's hard understand the concept properly.. im glad i found this vedio ❤❤

@TheScienceClassroom

8 ай бұрын

😃 this can be a tough concept, great work!🎉

so marvellous.... lecturers don't go to this extent 🌹🌹

By far the best explanation out there!!

Thank you for your excellent explanation, it was very helpful.

great video!

thank you! this helped a lot

Genuinely useful and cute at the same time..no bluff..

Thanks! Great Explanation

Thanks ,you are really a good teacher 👍👍👍👍👍

great video but you said a hydroxide ion makes a base but really you should use the bronstead-lowry definition for this level chemistry

Where did the .09898M value come from for the reactants part in the Ka equation??

@faithakoth7391

2 жыл бұрын

0.10_1.32*10^-3

I love your video so much!!!!

@TheScienceClassroom

Жыл бұрын

Thanks! 🤗

Great video

This was so helpful.

I have a question. The concentration of HCl you mention in the video is the one remaining after the reaction completing or it is the total one of the initial HCl when the reaction has not happened yet? May your guys explain it for me? thanks a lot

@aydis1s-li9dt

Жыл бұрын

We calculate the ka when the reaction is in equilibrium [HCL]final

@Redpanda.1403

Жыл бұрын

@@aydis1s-li9dt I understand now. Thanks!

@TheScienceClassroom

Жыл бұрын

aydis1s-li9dt already answered, but just wanted to say that they are correct!💯

what about the volume? i thought to use that Ka equation we needed concentration and concentration=moles/volume. i dont know just want help. thank you

thnq u sir . keep on uploading !!

Thz Sir,however I have a question, for example if the dissociation constant of water is 1M`2 , it means 1 mole of hydrogen and hydroxide ions are present in 1 litre of water at 25°C.(btw I knew the number is incorrect).So, my question is if the dissociation constant of a certain acid is 1M, which stands for mol and which stands for 1 dm3 of solution?

Cant we use pka=-logka or something instead of the ice table?

Great Chart

What would the Ka be of a buffer solution? Would it still follow the same process or is it always going to be some value?

@charliemagdics6980

2 жыл бұрын

poo

0:18 The Joker was here.

since HCl is a strong acid so we can't write HCl in the denominator. And so we can't calculate Ka for strong acids like HCl. Its Ka is infinite. Is not it?

@TheScienceClassroom

8 жыл бұрын

+Qudratol Wazir You are correct. HCl is a strong acid and essentially dissociates completely. We would never actually calculate the Ka for HCl because our answer would be nonsensical. We can still write the equilibrium expression for the dissociation for HCl because theoretically, nothing dissociates completely. It is reported that the Ka for HCl is 1.3 x 10^6 depts.washington.edu/eooptic/links/acidstrength.html. I'm not entirely sure how this value was determined (for a Ka, it is essentially infinite since it is greater than 1).

Am saving this video for my mates😂👌🤲

Please: where did 0.09868M came from. Thank you ! )))

I was good until you lost me at 0.09868 M. How did you get that number? Can you please show me step by step on the calculator. Please! thank you

@_loci1_avoidkv28

7 жыл бұрын

He subtracted 0,00132 from 0,1.

@bxglizzo8

7 жыл бұрын

thank you so much!!!

@_loci1_avoidkv28

7 жыл бұрын

Amy Loc You're welcome!

@sharadapalangappa5450

4 жыл бұрын

Hhghbh

Nice

why didn't you add the 1.32x10^-3 before subtracting them from the .1M? The H+ and CH3COO- are both 1.32x10^-3. If they ended up with a 2:1 instead of 1:1 ratio, wouldn't that change the answer?

at 3:18 you say that the biggest value Ka could be is 1...but wouldn't that mean that only half the acid is dissociated (same number in denominator and numerator)? Thanks!

@MatthewLaberge-po2cz

3 ай бұрын

That means 1/1, which is 100%, not 1/2

Bruh, it was asked to find the dissociation constant instead association one. But it does not matter/ Thank you man)

Bro what is the use of ka ...what dose it telll you you find it what dose it imply

How do you get the 0.09868M ?

Then, what do I do with it.

Why didn't you do double arrows this reaction is not one way smh

i dont get how the [H+] of 1.32x10^-3 became a change in concentration

@alexandery8508

4 жыл бұрын

Are you confused of how c.H+ went from 0M to 1.32x10^-3M? The professor took the fact that the concentration would be the same for the products according the same coefficient. You need to understand what more about the coefficients.

@alexandery8508

4 жыл бұрын

Or are you confused of how this could be a change? It is a change from 0 (which u didn't think) and it is not a change from 1.32 x 10^-3, yes.

@alexandery8508

4 жыл бұрын

The professor meant the change between 0 and 1.32x10^-3.

@alexandery8508

4 жыл бұрын

0 is a substitute for x

I got 1.77x10-6

Where did you get 10^-5? in the final answer of Ka = 1.77×10^-5 hope this will be answer 😞

@itzjowii

Ай бұрын

Could you explain what you don’t get so I can try to help

where'd he get E=0.09868 M?

What is pka

@Tudi500

6 жыл бұрын

pka is the value of a substance where half of the substance is in loaded form and half is uncharged form.

@TheElectrozoid

6 жыл бұрын

it is the -log(Ka). the smaller the pKa of something, the stronger an acid it is.

Who is from India here

@sameershahab1940

5 жыл бұрын

But I am Indian

@celeste2221

2 жыл бұрын

Not me✌️

HA HA HA HA HA HA

Lis t strong acids

Sam is a chungus

@jewswrld9732

5 жыл бұрын

Samuel Goldberg shut up concert band material

@jewswrld9732

5 жыл бұрын

Samuel Goldberg really? Last time I checked people play you like you play the tuba

Send help. HA HA HA