Absolute & Local Minimum and Maximum Values - Relative Extrema, Critical Numbers / Points Calculus
This calculus video tutorial explains how to find the absolute minimum and maximum values as well as the local max and local min. It explains the extreme value theorem for finding absolute extrema and discusses the first derivative test to identify relative maximum and minimum values using a sign chart on a number line. It also discusses how to find the critical points or critical numbers of a function. This video contains plenty of examples and difficult / hard practice problems.
Introduction to Limits:
• Calculus 1 - Introduct...
Derivatives - Fast Review:
• Calculus 1 - Derivatives
Introduction to Related Rates:
• Introduction to Relate...
_____________________________
Extreme Value Theorem:
• Extreme Value Theorem
Finding Critical Numbers:
• Finding Critical Numbers
Local Maximum & Minimum:
• Finding Local Maximum ...
Absolute Extrema:
• Finding Absolute Maxim...
Rolle's Theorem:
• Rolle's Theorem
________________________________
Mean Value Theorem:
• Mean Value Theorem
Increasing and Decreasing Functions:
• Increasing and Decreas...
First Derivative Test:
• First Derivative Test
Concavity & Inflection Points:
• Concavity, Inflection ...
Second Derivative Test:
• Second Derivative Test
_________________________________
L'Hopital's Rule:
• L'hopital's rule
Curve Sketching With Derivatives:
• Curve Sketching - Grap...
Newton's Method:
• Newton's Method
Optimization Problems:
• Optimization Problems ...
_______________________________________
Final Exams and Video Playlists:
www.video-tutor.net/
Full-Length Videos and Worksheets:
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Пікірлер: 152
Final Exams and Video Playlists: www.video-tutor.net/
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2.71 million subs aren't enough...I passed both AP and honors chemistry, Algebra 1,2 and 3 enhanced, and AP calculus just by watching your videos. Not to mention, I also show the Investment Club I lead your investment and stock videos as well. Thank you so much, God Bless.
@cubit404
Жыл бұрын
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@jnb3451
Жыл бұрын
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@3rdDegree_
7 ай бұрын
2 years later, he has the same numbers just in a different order. At 7.21m subs now!
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@powerToYourself36
3 жыл бұрын
@@Anthony-bn1go I did that intentionally grammar police :P.
@powerToYourself36
3 жыл бұрын
@Arc10 lol
@christiancardenas3261
3 жыл бұрын
@@powerToYourself36 Wow noob. Still responding to replies 2 yrs later🤧
@powerToYourself36
3 жыл бұрын
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@user-fx4jj3id1u
3 жыл бұрын
@@powerToYourself36 u still find the organic chemistry guy useful to u ? even after 2 years? and what are u studying right now ?
When my friends asked me how do i get so good at calculus, i simply answer. “Im just an apprentice to a Calculus god on youtube”
@ghhjjhjjjhujjvfhm7962
3 жыл бұрын
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@m.amirulhakim7406
3 жыл бұрын
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3 жыл бұрын
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@slimey_37
2 жыл бұрын
Cringe bro
@milotura6828
Жыл бұрын
I AM BUT THE APPRENTICE
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OK. You corrected it. I was wondering why no one mentioned it earlier.
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that is a historical moment 36:45
@lauralang3113
3 жыл бұрын
lol, he made a mistake!
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Very helpful
awesome, now do it with trig max and minimums !!
41:33, I am confused why 0 is part of the critical points. Wouldnt it just be -1 and 1?
you are amazing
I have a query. at 3:58 we have a graph which does not have a minima as last point is encircled and therefore is not part of the graph but the point before that is included in the graph so why we don't consider it as a minima. Thanks in advance
I am a normal student,I see this dude's video,I like
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14:08 you said if the leading coefficient has a odd power like x^3 then it will have no max or minimums. but at 22:21 that function also has a leading coefficient with odd power of ^3 but that one has a max and minimum for some reason?
For the last problem I dont think you would include -3/2^1/2 because it is equal to -2.1 which is outside the restricted domain. so there would be no local min and -2 would be the absolute min. Correct me if Im wrong.
@SM-qn7sr
2 жыл бұрын
At 1:09:00 he said it’s not part of the interval
@36.12 it should be minus 12(0) i.e -0 and not +0 as stated in the question but more importantly perhaps @ 3.27 which should be -12(2) and not +12(2) ...... -24 and not +24 hence final answer @36.45 should be -7 and not +41.
@jimhalpert9803
4 жыл бұрын
Bruh he corrected it in the video itself.
Thanks 👍
@1:04:30 you keep using -3/sqrt(2) wich is -2.12 so its out of our intervall. Or did I do something wrong here?
@Loots1
5 жыл бұрын
no youre right, i think he just made a mistake
@misutokiriya6547
4 жыл бұрын
It's been like a year but for future uses, he did remove it in the end; thus, not making it the absolute minimum value in the interval [-2,3]
how is 5/3 present in 2/3? please explain
So like... does chain rule not apply to this because when you bring the exponent down don't you have to multiply the expression by its derivative-
Quick question: Wouldn't the square root of 9-(3)^2=0, which would create a domain issue?
Thank you for this video, nice explanations. One correction: f(2) = 3(2)^2 - 12(2) + 5 = -7 actually, not 41. Cheers!
@user-bw1jn1yc1i
7 ай бұрын
Whoops, just saw your in-video correction. No worries!
on 57:26, shouldn't the graph be restricted on the interval [-1,2]? Why did you make it continuous on all real numbers?
This video has saved me in my darkest hour
Thanks G
what will we do when we have modulus function
Thanx
What if we have two minimums, but they are "the same"? (-1, -1) and (1, -1). Are both absolute minimum? Or are they both local minimum?
52:10 If you want to shave (valuable) seconds off (while getting a better idea visually/kinestheticly), don't bother wasting time "testing points" to find out where the derivative changes sign. Simply quickly plot the (*numerator of the) derivative, ie plot f' vs x. Just use end behavior and the zeros to do this. (*Yes, there is something in the denominator in this particular example because we are dealing with a rational function, but in this example the denominator is always positive, so it won't affect finding where f' changes sign. Keep in mind, that you can avoid "testing the points" 100% of the time if dealing with a polynomial function.)
thank u
Very nice but on 7:20 you said if f'(c) doesn't exist, we have a cusp. Not necessarily coz we might have vertical tangent just like in f(x)=x^(1/3) at x=0 . So how can we tell if we have a cusp or vertical tangent?
@SM-qn7sr
2 жыл бұрын
its a cusp because if f'(c) doesnt exist at x=a certain number then its not differentiable at that number and not differentiable means the first derivative isn't continuous on x=that number. Its only a verticle tangent if f(x) is undefined, not f'(c)
God bless you
52:25 if you plug in 1 the answer is gonna be negative no ?
In 27:55 it's super complicated.
8:82 Shouldn't the lower local min be a critical number instead?
57:50
whoever dislikes his videos will never be able to learn anything in life.
@jimhalpert9803
4 жыл бұрын
Dislikers are probably the rival educational youtubers lol
@ghhjjhjjjhujjvfhm7962
3 жыл бұрын
No just hate your comments If someone commented it id probably like it A hole
Him: "and the value is 46" Me: "OH MY GOD WHAT DID I DO WRONG HOW DID HE GET THAT"
Please, do you have to find the X and Y intercepts to draw the graph with accuracy? If so, then how do I find my X_intercept for 2x^4 - 2x^2 - 1=0? Thank you
@TheOrganicChemistryTutor
7 жыл бұрын
It doesn't look factorable. You can use the quadratic formula where a = 2, b = -2, and c =-1. The result that you get will equal x^2 and not x so you will have to take the square root of that result to get the final answer. You can also graph it using an online graphing calculator and find where it touches the x axis. Go to google and type in 'online graphing calculator' and the choose the first link that comes up which is desmos.com. Type in the expression "2x^4-2x^2-1" without the =0 part and you should see the graph. Move the mouse to the point where the graph touches the x - axis and you should see the answer. x = +1.169 and -1.169. I hope that helps :)
@emkayvevo4950
7 жыл бұрын
Thank you.
44:30
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what program do you use to do the video?
@TheOrganicChemistryTutor
5 жыл бұрын
It's in this video: kzread.info/dash/bejne/pHaH16-on7C_otY.html
Hi, for the first problem you did, does it matter which number you plug into the first derivative? You did plugged in a # that is smaller than 1.5 into 2(2x-3). If I plug in a # that is smaller that 1.5 into 6x-6, would I still get the same answer as you? Thank you!
@ghhjjhjjjhujjvfhm7962
3 жыл бұрын
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Does absolute max/min mean global max/min?
question on the laast problem..................................why would you include -3/2^1/2 ???? its already beyond -2???? please answer??organic chem plssss
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@jimhalpert9803
4 жыл бұрын
Patreon
Physics C E&M Playlist?
36:45 he switch the -12 to +12 did anyone noticed ?
Thankyouuuuu🥺❤️
31:08
🙌🙌🙌
I feel like I should be paying him
@dareal2669
4 жыл бұрын
Lol same
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