3 steps easy. Drop a perpendicular from A to meet BC at E. 13^2 = h^2 + (x+h)^2 = h^2 + x^2 + 2xh + h^2 10^2 = h^2 + (x-h)^2 = h^2 + x^2 - 2xh +h^2 Subract these equations 160 -100 = 69 = 4xh The area of ABC is 2xh/2 = xh = 69/ 4

Appolonius theorem will work ryt? And then find area by herons formula

Thank you very much

The area of a triangle is half the base times the height… x is half the base, and the height is y/sqrt2. You got xy at 16:42, and the area is x.y/sqrt2 = 69/4.

Nice.. it would be better, if you could explain where this will be used in practical life in the lecture.

@gandelve

5 ай бұрын

It's basic practice. Imagine you were building a bridge. In the middle of the river you could build a pylon to support two halves (which were the same size because of industrial pre-fabrication). And you would support the bridge with a 23m cable from a point which was off-center. And so on. If you can't solve this problem, you will never be an engineer.

@dickroadnight

5 ай бұрын

You would not need the area to build a bridge. It could be a surveying or building problem… you need the area for paint, concrete etc.

@alokranjan4149

5 ай бұрын

Very beautiful practical application 👍👍

69/4.

69:4