Hello Maths 505, W means win and chat is a part of live streaming where they can talk in real time (as in text)

I’m just finishing up Calc I at the moment but these videos have been endlessly intriguing and I’ve learned more math than I ever had in school from watching your content. Thank you for making such good content! (even if you can’t draw zetas)

The final result is correct, but presented with integration bounds 0..1, as opposed to 1..e in the original task.

5:48 yields another interesting and as of yet unsolved integral! Just \int_0^pi/2 Deceivingly difficult!

Here is a time stamp for your crucial steps, and btw I'd love to see more of these integrations. Great Job 00:02 Solving integral using log X substitution method 01:10 Substitution of 1-u for T opens up new avenues for solution development. 02:07 Transformation and equivalence of gamma function-based integral 03:11 Relation between gamma functions and Euler's reflection formula 04:22 The integral is transformed using a substitution method. 05:34 The integral is transformed using symmetry and a neat little transformation. 06:39 The integral is related to a famous logarithmic trigonometric expression. 07:46 Simplified the integral to 1/2 of log 2

@maths_505

17 күн бұрын

Damnnnnnnn....thanks bro

Hi, "ok, cool" : 3:38 , 5:29 , 7:41 , "terribly sorry about that": 5:36 , 6:43 .

@maths_505

18 күн бұрын

Only 2 terribly sorrys???? UNACCEPTABLE FROM ME I NEED TO UP MY GAME TERRIBLY!!!

@daddy_myers

15 күн бұрын

​@@maths_505You forgot to add "terribly sorry" at the end.

Thank you for your continuous and fruitful effort.

lovely!

Try this one: integral from -pi to pi of e^(p sin(x)) * cos(a+pcos(x)) dx. Here a and p are any real numbers.

Very cool!

That was _awesome_ ! I confess I expected to see the reflection formula show up as soon as I saw the thumbnail (how could it not, with a Gamma(1-ln(x)) in the integrand?), but I hadn't figured out how you were going to get there until you were almost there. How long did it take you to construct the integral to give you that result?

@maths_505

18 күн бұрын

This one about 5 minutes 😂

Your "zeta" ζ, looks like a xi: ξ.

@maths_505

18 күн бұрын

Which is supposed to be harder to write than zeta 😂

i tried before watching, and I checked the answer by watching the video . answer matched. thanks for teaching all of us . i have been improving my problem solving ability in maths by watching ur videos. thanks mate. 😊 also how's ur studies going in university?

@maths_505

17 күн бұрын

It's going good alhamdullilah....things do get hectic but I use whatever free time I get to make videos. And I'm happy I could be of some benefit to you guys.

@aravindakannank.s.

16 күн бұрын

@@maths_505 keep grinding.

8:43 - integral from 1 to e (not from 0 to 1)! 😛

bro got so much thing on his mind lmaooooo

May you make explanation for calcus 2, 3, 4 ?

@maths_505

18 күн бұрын

What's cal 4? I studied cal 3 (multivariable and vector calculus)....not sure which countries call that cal 4 though.

what app do you use to do math?

Could you sometimes give numerical values for these integrals?

@maths_505

18 күн бұрын

What are numerical values (I heard they were a thing of ancient legend but I didn't believe they were real)

@tomaszkochaniec9421

17 күн бұрын

​@@maths_505Even funny...😂

W

Come te I=Int(lnΓ(u)du)0>1..io ho risolto per parti..I=0-int(uψ(u))..

Why do you hate brackets 😢

@maths_505

17 күн бұрын

I don't know 😂

what if the middle two functions were switched? I=int[1,e](ln(1-gamma(lnx))/x)dx u=lnx, du=dx/x I=int[0,1](ln(1-gamma(u)))du ln(1-x)=sum[n=1,♾️]((x^n)/n) I=int[0,1](sum[n=1,♾️](gamma^n(u)/n))du I=sum[n=1,♾️](1/n•int[0,1](gamma^n(u))du) i got nothing