A Nostalgic Problem Revisited With Sound 😁

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Пікірлер: 34

  • @leaDR356
    @leaDR35628 күн бұрын

    I chose 1 by observation

  • @doctorb9264
    @doctorb926421 күн бұрын

    Really like the emphasis on the graphs.

  • @farhansadik5423
    @farhansadik542328 күн бұрын

    epic video! Would you tell me what application you use for making these? I recently got a drawing tablet and want to imitate you in a mirror lol

  • @phill3986
    @phill398628 күн бұрын

    😊😊😊👍👍👍

  • @BlaqRaq
    @BlaqRaq28 күн бұрын

    It (exponentialize) will, more likely, show up in the dictionary on Friday. Remember, the different departments it has to pass through?

  • @SidneiMV
    @SidneiMV28 күн бұрын

    x = cosu => x² = cos²u

  • @SidneiMV
    @SidneiMV28 күн бұрын

    WOW! Domain! Domain!!

  • @YouTube_username_not_found
    @YouTube_username_not_found28 күн бұрын

    The first method is definitely more elegant!

  • @hazem1el_abed
    @hazem1el_abed28 күн бұрын

    8:28

  • @fahrenheit2101
    @fahrenheit210128 күн бұрын

    1 is an obvious solution, and a graph sketch confirms it's the only one, since sqrt(1 - x^2) would have a upper semicircular graph, and exponentiating preserves order, so the graph shape would still be "up then down", enough to ensure 1 is the only solution. Though and algebraic approach escapes me, so ... time to watch.

  • @johns.8246
    @johns.824628 күн бұрын

    If p is prime, when is 7^(3p) - 2^(3p) a multiple of p?

  • @moeberry8226
    @moeberry822628 күн бұрын

    I want to point out that critical points are not just were the function has a zero slope but rather where the slope is also undefined and that can happen at points of discontinuity, a sharp cusp or a vertical tangent.

  • @DonEnsley-mathdrum
    @DonEnsley-mathdrum28 күн бұрын

    X=1. The negative solution of -1 doesn't work.

  • @rakenzarnsworld2
    @rakenzarnsworld228 күн бұрын

    x = 1

  • @tunistick8044
    @tunistick804428 күн бұрын

    8:26

  • @peskarr
    @peskarr28 күн бұрын

    too easy, solved with halfcircle in 1 minute