#32 IIT JEE Advanced 1986 Common Root | Abhishek Mishra
Learn concepts through solving IIT JEE Advanced Problems. In this video series I am explaining concepts through solving previous year IIT JEE Advanced problems. This series is a must watch for JEE Aspirants.
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Пікірлер: 14
Sir please continue series
I did it this way ( a-b) ^2=(b-a) (a^2-b^2) (a-b) (a-b) =(b-a) (a+b) (a-b) (a-b) =(b-a) (a+b) -i Taking b-a value from above (a-b) /(a-b) ^2/a2-b2 a+b=a-b Putting in I b-a=1 Multiplying by negative a-b=-1=a+b
Sir please continue this series Everyday i used to watch these lectures, they are perfect in clearing the concepts Try to continue this asap sir :)
Sir apka PhD kb hoga khtm
Easy peasy
Bhaiya theorem ko learn kaise kare
I have the same prof. For physics. i.e. PKK - Keshav Khatri Sir
Hello bro can you please start an english batch for dropper of jee 2022
can we apply this process in all types of common root problems
@AbhishekMishraiitkgp
3 жыл бұрын
If it's useful, then yes
@skandkumar9756
3 жыл бұрын
@@AbhishekMishraiitkgp bhaiya we can apply cramers rule also when we want answer without any major thinking
Hlo bhaiya mera name zainul hae aur mae 11th me hu jee ki tayyari kr rha rhu to kya mujhe aap koi tips de skte hae
@icyy9864
2 жыл бұрын
Padho
Muje lagta hai apki PhD khatam hojayegi lekin quadratic nahi khatam hoga.