If each one was repeated only two times it would be easier, since in that case I believe XORing the entire array together would give you the single number

@deepcodes

Жыл бұрын

Yes, absolutely!

i did this one before but didnt got any clue of how to do it with constant space now i know

Very well explained

@deepcodes

Жыл бұрын

Thanks for liking

you can use ans = ans | (setBits

@deepcodes

Жыл бұрын

Yes, good thought!

Could you please explain why you took ans as long?

Instead of calculating pow every time, we can maintain long long shift and multiply it by 2 each time in the loop. It will save time,ig.

@deepcodes

Жыл бұрын

Yeah, we can.

will this work on negative numbers ?

bhaiya kon sa pen tab use karte ho aap

@deepcodes

Жыл бұрын

XENX pen tab